Author 
Message 
Martin

Posted: Sat Apr 26, 2003 11:37 am Post subject: Sine inverse 


Is there any way I can use sine inverse with turing? My problem is this:
I know the starting and ending points of a line, and I need to find the angle formed...ex:
code: 
(x2,y2)
/ 
/ 
/ 
/ 
(x1,y1)/ m_____

solving for angle m
bleh the diagram's not too great, but I'm sure you get the idea 





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JSBN

Posted: Sat Apr 26, 2003 12:20 pm Post subject: (No subject) 


u could use cos or sin ratio to figure it out, there is a tutorial for it.
and if u need the length of the angled line u could use pythagorium thyrum: A^2 + B^2 = C^2 





octopi

Posted: Sat Apr 26, 2003 1:08 pm Post subject: (No subject) 


Had one way, but this ones much better.
code:  function arcsin ( x : real ) : real
if (x = 1) then
result 90
else
result arctand(sqrt(abs((x*x) / (1  (x *x)))))
end if
end arcsin
function arccos ( x : real ) : real
if (x = 0) then
result 90
else
result arctand(sqrt(abs((1  (x *x)) / (x *x))))
end if
end arccos
for i:1..90
put arccos(cosd(i)) ..
put " " ..
end for 
Modified it to work with 1, and 0 





jamez

Posted: Sat Apr 26, 2003 7:54 pm Post subject: (No subject) 


octopi your code crashes 





octopi

Posted: Sat Apr 26, 2003 8:10 pm Post subject: (No subject) 


Not for me, what version do you use, and are you modifying it at all?
I test in winoot 3 only. 





nate

Posted: Sat Apr 26, 2003 8:15 pm Post subject: math 


The reason its crashin is cause when you reach 90 degrees.
It messes up cause your dividing by 0.
Basically you don't you arcsin or arctan for something that is at 90 degrees?
???
Well, i am only in grade 9 so how do i know? (thats what i think)
???
Nate 





Tony





octopi

Posted: Sat Apr 26, 2003 9:04 pm Post subject: (No subject) 


The weird number isn't that weird....
its:
1.207418 raised to the 6
(also known as)
0.000001207418
So virtually zero. 





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