Sine inverse

[Martin]

Is there any way I can use sine inverse with turing? My problem is this:

I know the starting and ending points of a line, and I need to find the angle formed...ex:

code:

(x2,y2)                / |              /   |            /     |          /       | (x1,y1)/ m___|__

solving for angle m

bleh the diagram's not too great, but I'm sure you get the idea

[JSBN]

u could use cos or sin ratio to figure it out, there is a tutorial for it.
and if u need the length of the angled line u could use pythagorium thyrum: A^2 + B^2 = C^2

[octopi]

Had one way, but this ones much better.

code:

function arcsin ( x : real ) : real   if (x = 1) then      result 90   else      result arctand(sqrt(abs((x*x) / (1 - (x *x)))))   end if end arcsin function arccos ( x : real ) : real   if (x = 0) then      result 90   else      result arctand(sqrt(abs((1 - (x *x)) / (x *x))))   end if end arccos for i:1..90    put arccos(cosd(i)) ..    put " " .. end for

--Modified it to work with 1, and 0

[jamez]

octopi your code crashes

[octopi]

Not for me, what version do you use, and are you modifying it at all?

I test in winoot 3 only.

[nate]

The reason its crashin is cause when you reach 90 degrees.
It messes up cause your dividing by 0.

Basically you don't you arcsin or arctan for something that is at 90 degrees?

???
Well, i am only in grade 9 so how do i know? (thats what i think)
???

-Nate

[Tony]

Nate is right, but you need a function that works for 360+ degrees

so all you have to do is place a guard in the function...

code:

function arcsin ( x : real ) : real if x*x not= 1 then   result arctand(sqrt(abs((x*x) / (1 - (x *x))))) else     result 90 end if end arcsin

although it still outputs a weird number instead of 0. I suppose it has something to do with the fact that its impossible for arcsin to be 0

[octopi]

The weird number isn't that weird....
its:

1.207418 raised to the -6
(also known as)
0.000001207418
So virtually zero.