Having collision problems and [why laws of universe r wrong]

[Axarent]

I'm a newb to programming and was wondering if anyone could give me suggestions on how to do collisions for hitting a target that you've shot at. I've been trying and just can't get it to work. Thx

[Tony]

we got tutorials on rectangle and circle colision detections available... all depends on what kind of target you're trying to hit and with what.

[Axarent]

well I was trying a space shooter with a moving enemy picture that I drew in paint and flys across the screen. i'm using draw line to create the shot should I try to use draw oval and box to make the enemy to make it easier??

[Tony]

well you could treat the ships as circles (keep the picture though) and use equations y = mx + b and x^2 + y^2 = radius to see if your lazer line intersects the ship or not.

[Axarent]

so would I use the coordinates of my laser line for y and x in y=mx +b and the coordinates of the enemy for x and y in x^2 + y^2 = radius and then check if the line intersects the diameter at anytime right??

[Tony]

yeah, but as bugz pointed out in another post, I got forumulas mixed up a bit...

for the line, its better to use Ax+By+C=0 I think...

circle is (x-a)^2 + (y-b)^2 = radius^2 where a/b are x/y of circle's center.

[PaddyLong]

radius^2 you mean for the circle

[Andy]

uhoh tony, forgetting rade 10 math eh?

[Martin]

And rade 9 english, dodge

[Tony]

huh? it says

Quote:

= radius ^2

did anyone else read 1984? Great book

[Andy]

riiite that's y it says last edited by tony... ya its an awsome book, big brother's watching u...

[Grey_Wolf]

1984 is a great book. What does that have to do with anything.

[PaddyLong]

1 + 1 is only 2 becuase we've been trained to believe it (or somethign to that effect... haven't read the book for a while)

[Andy]

hey man, tony owns the site, he can say any thing he wants..

[Tony]

it was 2+2=5... and those guys are right... here's the math proof behind it (someone had part of this equation as their signature)

assume x = a
x^2 = ax
x^2 - a^2 = ax - a^2
(x+a)(x-a) = a(x-a)
x+a = a
x + x = x
2x = x
2x + x = x + x
3x = 2x
5x - 2x = 2x
5x = 2x + 2x
*divide both sides by x
5 = 2 + 2

So teachnically... the book is telling the truth. 2+2 does equal to 5.