a = 3 values out of 5 values

[person]

i was wandering if ther was a command that does this

if (a= 3 out of the 5 values) then

[Tony]

Turing:

for i:1..5      ...

[person]

can u elaborate? cuz i dont understand

[Tony]

actually what you can do is..

take your 5 values and sort them to be in order. Now for the condition to be true, a would equal to the 3rd and ether 1st or 5th.

pseudo:

sort(values) if (a == values[3] and (a == values[1] or a == values[5] )) then    //success!

[md]

in psudo code...

code:

int good_count = 0; for i = 0 to 5 do     if test[i] == true         good_count++; if good_count >= 3     // this is where your code goes

you can also do it without a loop:

code:

int good_count = 0; if cond_1     good_count++; if cond_2     good_count++; if cond_3     good_count++; if cond_4     good_count++; if cond_5     good_count++; if good_count >= 3     // your code

[person]

so i have to type that so many times? (im making holdem, and i want to check for a 3 of a kind)

[md]

how do you store cards? There are lots of ways to simplify card functions, depending on how you represent a card. However, I must point out that the code above is fairly simple and short...if you're going to complain about 15 lines then I'm not sure how your going to write any actual programs...

[1337_brad]

What if you save all the cards to an array, and then check the array for 3 cards... D: seems efficiant.

code:

var Player1hand : array 1..5 of int   % 5 cards in the players hand var HowManyOfEach: array 1..13  of int % 13 possible cards in the hand %(ace-king) %put code here to get the values to the array for i: 1..5      HowManyOfEach(Player1hand(i)) += 1  % this adds one to the occurance %of cards array for whatever card is in the players hand end for if HowManyOfEach(1) > 3 then %code for 3 of a  kind aces elsif HowManyOfEach(2) > 3 then %code for 3 of a kind twos, and just repeat this code for all the hands..

[/code]