Need Help with Turing

[SAValkyrie]

What is it you are trying to achieve?
Trying to write a program that endlessly tells you to "Have a good day"
Tr y stopping execution. Change it so that it is a program to wish you a good day only six times.


What is the problem you are having?
I got the "Have a good day" part but I cannot figure you the only six times part. With my knowledge, the only thing i can do is to state the word that can stop the execution. Is there a way to stop it when it counts 6 times?



Please specify what version of Turing you are using
Turing 4.1.2

[chipanpriest]

Either look into increments. or if you're really adventurous, look into for statements.

I'll give you this much, to exit a loop, you can type "exit when". Eg.

Turing:

loop exit when %whatever end loop

You can set the whatever to anything you want, which can help in your situation.

Think about it, if you want the loop to exit after 6 times, how would you get the loop to count?

[SAValkyrie]

Turing:

for count:1..6

Is the use of count appropriate in this situation?[/syntax]

[Tony]

Yes, you can use for-loops to execute a piece of code a specific number of times.

[SAValkyrie]

Turing:

var count:int count:=0 loop     count:=count+1     put "Have a good day"     exit when count=6     Time.Delay(500) end loop

ah i got it[/syntax][/quote]

[chipanpriest]

LOL your second comment was different than your first. Both work though. You could use a for statement:

Turing:

for count : 1 .. 6 put "Have a good day!" Time.Delay (500) end for

I like this better but both ways work.