Rounding minutes

[BiggZigg9]

Hey can anyone help,
So i have to do this short turing activity which involves calculating the cost of a long distance call. My problem is i dont know how to make it so that 1 sec = 1 min, 61 sec = 2 mins ect. HELP please

Thanks

[2goto1]

The modulus operator might be your friend here

[Zren]

ceil() is the function your looking for. Also it's opposite function is floor() is case you were wondering.

Edit: Also I think 2goto1 meant using Integer division. Added to the example.

Eg:

Turing:

View.Set ("offscreenonly") var t : int var seconds : real loop     cls     t := Time.ElapsedCPU     seconds := t / 1000     put "Miliseconds: ", t     put "Seconds: ", seconds     put "Ceil: ", ceil (seconds), " seconds"     put "Floor: ", floor (seconds), " seconds"     put skip     put "Integer Division: ", t div (1000), " seconds"     View.Update end loop

[BiggZigg9]

no like i need to make it so that when the person puts in eg) 61 seconds the program beconizes it as 2 mins?

[Tony]

Yes, you are looking for ceil type rounding.

[BiggZigg9]

okay well i am a huge noob at turing so haha.......

[2goto1]

yah ceiling better than modulus in this case

[Insectoid]

This is a common problem called the Pigeonhole Principle. It pops up all over the place, so learn it and remember it.

[Tony]

Pigeonhole Principle is a construct used in many proofs, not really "a problem". I don't follow how this is applicable to mod/ceil