Loop Fail

[ProgrammingFun]

I can't think of any way to do this in a more efficient way (perhaps using for-loops)...so I posted to ask, is there a better way to do this?

Java:

checkBoard[0][0] = gameBoard[x-1][y-1];             checkBoard[0][1] = gameBoard[x][y-1];             checkBoard[0][2] = gameBoard[x+1][y-1];             checkBoard[1][0] = gameBoard[x-1][y];             checkBoard[1][1] = gameBoard[x][y];             checkBoard[1][2] = gameBoard[x+1][y];             checkBoard[2][0] = gameBoard[x-1][y+1];             checkBoard[2][1] = gameBoard[x][y+1];             checkBoard[2][2] = gameBoard[x+1][y+1];

[Tony]

If by "more efficient" you mean "less lines of code", then yes. Two for-loops and a single assignment statement.

Edit: strictly speaking, you can do this with a single for-loop, at the cost of readability.

[Insectoid]

A nested for loop should do the trick.

code:

for x_ : 0-2 {     for y : 0-2 {         checkerBoard[x_][y] = gameBoard[x+y-1][x+x_-1]     } }

[ProgrammingFun]

Thanks for the help. I used the following method:

Java:

for (int a = 0; a < 3; a++) {         for (int b = 0; b < 3; b++)         {                 checkBoard[a][b] = gameBoard[y + b - 1][x + a - 1];                 System.out.print (checkBoard[a][b] + " ");         }                                         }

[ProgrammingFun]

An unrelated question:

If nowin is a boolean will:

if (nowin) mean the same thing as if (nowin == true)

if (!nowin) mean the same thing as if (nowin == false)

Thanks for the help!

[2goto1]

Yes and yes. Try spitting out each to your console to confirm

[ProgrammingFun]

2goto1 @ Sat Jan 08, 2011 5:24 pm wrote:

Yes and yes. Try spitting out each to your console to confirm

OK, thanks for the help...

[copthesaint]

Tony wrote:

If by "more efficient" you mean "less lines of code", then yes. Two for-loops and a single assignment statement.
Edit: strictly speaking, you can do this with a single for-loop, at the cost of readability.

Sooo...
Does this work for yea then SAVES 1 LINE!!! *not counting brackets*

Java:

for (int i = 0; i < 9; i++){ heckBoard[((i-(i%3))/3)][(i%3)] = gameBoard[y + (i%3) - 1][x + ((i-(i%3))/3) - 1];                 System.out.print (checkBoard[a][(i%3)] + " "); }

Lol I dont want to know how complex it would be to minipulate the values for a 3 dimensional array doing this... lol

[DemonWasp]

Incidentally, always choose readability over number of lines of code. In fact, choose readability over anything except a real requirement.

[Tony]

copthesaint @ Mon Jan 10, 2011 3:31 am wrote:

Lol I dont want to know how complex it would be to minipulate the values for a 3 dimensional array doing this... lol

You weren't around for this, but things very quickly get out of hand... http://compsci.ca/blog/your-computer-science-isu-in-20-lines/

[copthesaint]

Lol, that is really great tony... , Also DemonWasp, whats the fun in readability jk