Giving a single variable the value of two other variables?

[m84uily]

code:

var streamA, streamB, streamC, count : int var numberA, numberB, numberC : array 1 .. 8 of int var aA, bA, cA, dA, eA, fA, gA, hA, aB, bB, cB, dB, eB, fB, gB, hB, aC, bC, cC, dC, eC, fC, gC, hC : int open : streamA, "C:\\A.txt", get open : streamB, "C:\\B.txt", get open : streamC, "C:\\C.txt", put for i : 1 .. 8     get : streamA, numberA (i) end for for i : 1 .. 8     get : streamB, numberB (i) end for for i : 1 .. 8     numberC (i) := numberA (i) and numberB (i) end for for i : 1 .. 8     put numberC (i) end for

What I'm attempting to do with this code is give numberC(i) the values of numberA(i) and numberB(i).

So, assuming numberA(i) has values: 1, 2, 3
and numberB(i) has values: 4, 5, 6

What I would want numberC(i) to be like would be: 1, 2, 3, 4, 5, 6

Could anyone give me some ideas? Help is much appreciated.

[Insectoid]

Clever use of 2 for loops should do it.

for x: 1..length (numberA)
%fill in numberC's variables with numberA's
end for

for x : length (numberA)..length (numberB+numberA)
numberC (x) := numberB (x + length (numberA)
end for

Now, I only posted code because I couldn't think of a way to explain it. If a mod deems it worthy of removal, go ahead.

[m84uily]

insectoid @ Thu Mar 12, 2009 5:19 pm wrote:

Clever use of 2 for loops should do it.

for x: 1..length (numberA)
%fill in numberC's variables with numberA's
end for

for x : length (numberA)..length (numberB+numberA)
numberC (x) := numberB (x + length (numberA)
end for

Now, I only posted code because I couldn't think of a way to explain it. If a mod deems it worthy of removal, go ahead.

Thanks!

I find I am unable to use "length (numberA)" due to the error "Argument is the wrong type" by "length (numberA)" did you intend for me to replace that with "8" ?

Well I assumed so, and changed the values to 8 my code now looks like this:

code:

for x : 1 .. 8     numberC (x) := numberA (x) end for for x : 8 .. 16     numberC (x) := numberB (x + 8) end for

And will not run due to the error "Array subscript is out of range" which occurs on the line "numberC (x) := numberB (x + 8)" Hm, a little more help, or perhaps a bit of an explanation? Thanks in advance.

[Tony]

numberC(i) is declared to be an int

1, 2, 3, 4, 5, 6 is not an int

[m84uily]

Tony @ Thu Mar 12, 2009 5:51 pm wrote:

numberC(i) is declared to be an int

1, 2, 3, 4, 5, 6 is not an int

Oh! What is it? But if it's the comas you're referring to, then that's my fault, the values should really be 1 2 3 and 4 5 6 which combine to make 1 2 3 4 5 6.

[jbking]

I think you're not accounting for the length of one of the arrays. To take your example of A being {1,2,3} and B being {4,5,6} how is C supposed to only have 3 values? If you want to store {1,2,3,4,5,6} that is 6 values, not 3.

I think I'd define C to be the length of A + length of B, which I'll leave you to figure out how to set that.

[Tony]

I think the use of the term "number" in your code is misleading. If you mean something like "a b c" concatenated with "1 2 3" to make "a b c 1 2 3", then you are dealing with strings. Which is also not an int

[m84uily]

Tony @ Thu Mar 12, 2009 6:07 pm wrote:

I think the use of the term "number" in your code is misleading. If you mean something like "a b c" concatenated with "1 2 3" to make "a b c 1 2 3", then you are dealing with strings. Which is also not an int

I'll do a search for "concatenated" thanks.

[Insectoid]

Concatenation is just joining 2 or more strings together.