DICE Help

[Kira]

I'm new to turing, and I need LOTS of help =( . Anyways, here is the problem I been figuring it out for hours....I just wanted the program to tell how many times the dice gets rolled continuously in order to get the same number.... but when I try the second time and third time and etc.....The times the dice gets rolled is added to the previous one....is there a way that it doesn't add the previous number of times rolled?

Turing:

var number, Result, count : int := 0 var reply1, reply2 : string loop     randint (number, 1, 6)     put "Do you want to play a dice game? (y/n) " ..     get reply1     exit when reply1 not= "y"     put "This will be your randomly chosen number from 1-6: ", number     delay (500)     loop         randint (Result, 1, 6)         delay (500)         put "It rolled ", Result         count := count + 1         if Result = number                 then             put "It rolled ", count, " time(s) to get the same number."             put "Do you want to try again? answer y or n " ..             get reply2             exit when reply2 not= "y"             randint (number, 1, 6)             put "This will be your randomly chosen number from 1-6: ", number             delay (500)         end if     end loop end loop

[Nick]

just reset count

count:=0

[Kira]

um, sorry....how do i rest count? do i enter count:=0 at the top?? ><

[Tony]

You use that line at whatever point in the program, where you want the count to be reset.

It would probably make sense to do something like this, right before the game begins.

[Clayton]

After you finish your embedded loop, (the one where you roll your "dice") just set count to zero again.

[Kira]

OMG THANKS SO MUCH... o yes one more thing....I got these dice faces pictures I wanted the program to show when a specific number on the dice pops up, is there a command that could make this happen? If so, what do I use and where do I input it in??

[Tony]

You should look into the proper usage of Pic.Draw()