CD Rom Limits

[MysticVegeta]

Hi, This question deals with which is the most efficient way to burn stuff on CD's. Its a Dwite Contest Question and i have part of the solution. Now it goes something like this, The first Integer in every line of 5 inputs states the CD ROM Capacity limit "c", and the second integer consists of how many things i want to burn on it "n" . The next integers are the number of "n" things and their capacity so it looks something like this ->

700 4 500 300 300 100
700 5 200 750 75 240 420
650 3 400 100 400
700 3 100 200 300
600 5 100 50 90 200 300

Here is the solution i have so far,

code:

var one : int var count : int := 2 var sum : int := 0 open : one, "Data4.txt", get var storage, items : array 1 .. 5 of int var cap : flexible array 1 .. 1 of int %Getting the variables for s : 1 .. 5     get : one, storage (s), items (s)     %Calculating the capacities     for x : 1 .. items (s)         get : one, cap (x)         sum += cap (x)         if x not= items (s) then             new cap, x + 1         end if     end for     %Processing for the greatest possible capacity in the loops     if sum > storage (s) then         sum := 0         loop             for ss : count .. items (s)                 sum += cap (ss)             end for             count += 1             exit when count > items (s)         end loop     end if     %Freeing the variables in the end and making the sum 0     free cap     put ""     sum := 0     count := 2     new cap, 1 end for

I have matched up ->
500 + 300 + 300 + 100
300 + 300 + 100
300 + 100
100

But i have no clue how match the rest of combos ->
300 + 300 + 500
100 + 500
........
........

Can anyone help? thanks

[MysticVegeta]

Any ideas?? I am sure a lot of people here have aced dwite contests. Please help