help with for statements

[battleroyale]

ok...for school, i need to make a mortage thing. Starting off with 120000 at 10.75% interest a year, i need to figure out when it will go down to zero if i pay 24000 a year. My teacher wants it like this

Year Beginnnig Balance Interest Payment Year End Balance


this is what i did so far

code:

var c:real:=120000 const it:real:=0.1075 const pay:int:=24000 for i:1..10     %how do i make it so it ends when c=0? put i, " ", c:5:2, "   " , c*it:5:2, "   ", pay:5:2, "  ", (c+(c*it)-pay:5:2 c:=c-(c*it) end for

how do i make it so the for statement ends when c=0?

[AsianSensation]

use the exit statement.

code:

exit when c = 0

[battleroyale]

If you meant something like this

code:

var c:real:=120000 const it:real:=0.1075 const pay:int:=24000 for i:1..100  put i, " ", c:5:2, "   " , c*it:5:2, "   ", pay:5:2, "  ", (c+(c*it))-pay:5:2 c:=c-(c*it) exit when c=0 end for

it doesnt work...it might be becuase of some eqaution but i dont know why. Help

[mike200015]

it ran fine?

your for loop goes from 1 to 100, at 100, c only = 1.55 so there is no need for your exit when c = 0

[c0bra54]

yeh but it ahs to goto zero, so just use maxint or anynumber lol, and then exitwhen c = 0 and makesure you include the last payment!

[battleroyale]

THis is what i did

code:

% var c : real := 120000 % % % const it : real := 0.1075 % const pay : int := 24000 % % put "Year", "      ", "Beginning", "    ", " Interest", "     ", "Payment", "      ", "Year End" % put "           ", "Balance", "       ", "Charged", "                   ", "Balance" % put "" % for i : 1 .. 7 % %     put " ", i, "      ", c : 10 : 2, "   ", c * it : 10 : 2, "    ", pay : 10 : 2, "     ", (c + (c * it)) - pay : 10 : 2 % %     c := c + (c * it) - pay % %     if c <= 24000 then %         put " ", i + 1, "      ", c : 10 : 2, "   ", c * it : 10 : 2, "     ", c : 9 : 2, "       ", c - c : 4 : 2 %     end if % end for

works out fine too....uncomment it first though