abc

[mercuryy]

How can you output something like

code:

A A A A A A * B B B B B * * C C C C * * * D D D * * * * *E E * * * * * *G

using counted loop?

* indicate space

[Cervantes]

What have you got so far? What are your ideas?
These problems are best for you to do. You don't learn if we give you the answer. But we can help you. So, on those lines, what are your ideas?

[mercuryy]

what i got is

code:

for decreasing row:26..1 for col:1..26-row put chr(row+64):3.. end for delay (56) put " " end for

but than i can't get it to "flip" to the other side. [/code]

[ssr]

I thnk what my teacher did on this quesion is do one loop for teh "*" and one loop for letters... 8)

[mercuryy]

yeah. but i tried that too.

code:

for  decreasing row:26..1 for  decreasing col:row..1 put chr(row+64):3.. end for put " " end for

here is another way i tried. but the ouput is still on the "wrong" side.

[Token]

yah we had to do this one too, heres a hint to how i solved it

code:

var letters :string :="ABCDEFG" var counter:int

then

code:

counter +=1 letters(counter)

also look up length in the help file, hope this helps

[ssr]

mercuryy wrote:

yeah. but i tried that too.

code:

for  decreasing row:26..1 for  decreasing col:row..1 put chr(row+64):3.. end for put " " end for

here is another way i tried. but the ouput is still on the "wrong" side.

my fault didnt explain it well
2 separate loops, I will post my code later on
eventually
...
yes
... 8)

[mercuryy]

so there are no other ways beside using the "length" function?

[Token]

i'm sure theres way more than that way, for example. maybe look at the chr and ord functions and think about doing a for statement somthing like

code:

for i:65..71

but really you need to look at the help file to understand that

[ssr]

lol ord and chr arent that hard

code:

var chars:char var ints: int get chars get :ints ord (chars) chr(ints)

it basically get a char and convert it into a ACSII number also it gets a ACSII number and convert it into a char.
***
I know u know how to do it token
just saying its not hard

[Token]

lol i know Sirui Song , i was just saying i didnt feel like explaining it t him so he'd have to look it up for himself but u took care of that for me didnt ya

[ssr]

lol, I knew I should spread my name all around the internet...

[Flikerator]

code:

var let : string := "ABCDEFGHIJKLMNOPQRSTUVWXYZ" for i : 1 .. length (let)     for ii : 1 .. length (let) + 1 - i         put let (i) ..     end for     put ""     delay (50) end for

Is that what you want? I don't think it is but maybe use it to do what you want?

[Token]

Flickerator thats basically what i did, only the thing is u have to do it the oposite way, so that they form against an imaginary margin on the right side, this is how i did it

code:

var letters : string := "ZYXWVUTSRQPONMLIJIHGFEDCBA" for decreasing i : length (letters) .. 1     for j : 1 .. length (letters) - i         put " " ..     end for     for j : 1 .. i         put letters (i) ..         delay (10)     end for     put " "     delay (10) end for

and you can change it to say ne thing u want, but it has to be backwards

[Flikerator]

Token wrote:

Flickerator thats basically what i did, only the thing is u have to do it the oposite way, so that they form against an imaginary margin on the right side, this is how i did it

code:

var letters : string := "ZYXWVUTSRQPONMLIJIHGFEDCBA" for decreasing i : length (letters) .. 1     for j : 1 .. length (letters) - i         put " " ..     end for     for j : 1 .. i         put letters (i) ..         delay (10)     end for     put " "     delay (10) end for

and you can change it to say ne thing u want, but it has to be backwards

Well you could take the original word and just make it backwords. That way you could ask the person for a word and they could still do it