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person
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 Posted: Wed Mar 09, 2005 6:00 pm Post subject: Integer overflow in real8 div. |
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how do i solve this problem when it says: "Integer overflow in real8 div."???
thanx in advance |
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Sponsor
Sponsor
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Flikerator
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| Posted: Wed Mar 09, 2005 6:06 pm Post subject: Re: Integer overflow in real8 div. |
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person wrote: how do i solve this problem when it says: "Integer overflow in real8 div."???
thanx in advance
Can I see the code? It might help to solve it ^^
Usually when I get overflow it is because the number is an int and its too large. |
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person
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| Posted: Wed Mar 09, 2005 6:07 pm Post subject: (No subject) |
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| code: |
var num : int
var ans : real := 1
var a := 0
get num
for x : 1 .. num
ans := ans * x
end for
for decreasing x : num .. 1
a := 0
for decreasing y : num .. 1
if (ans / x) / y = (ans / x) div y then % this line overflows
a += 1
end if
end for
if a = num then
ans := ans / x
end if
end for
var num : int
var ans : real := 1
var a := 0
get num
for x : 1 .. num
ans := ans * x
end for
for decreasing x : num .. 1
a := 0
for decreasing y : num .. 1
if (ans / x) / y = (ans / x) div y then
a += 1
end if
end for
if a = num then
ans := ans / x
end if
end for
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Flikerator
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| Posted: Wed Mar 09, 2005 6:10 pm Post subject: (No subject) |
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| I get an error message...Var previously declared. |
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person
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| Posted: Wed Mar 09, 2005 6:12 pm Post subject: (No subject) |
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D'oh (pressed ctrl+v twice)
anyways
| code: |
var num : int
var ans : real := 1
var a := 0
get num
for x : 1 .. num
ans := ans * x
end for
for decreasing x : num .. 1
a := 0
for decreasing y : num .. 1
if (ans / x) / y = (ans / x) div y then
a += 1
end if
end for
if a = num then
ans := ans / x
end if
end for
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person
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| Posted: Fri Mar 11, 2005 3:29 pm Post subject: (No subject) |
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| does anyone have any ideas to solving this problem?? |
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ssr
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| Posted: Fri Mar 11, 2005 3:52 pm Post subject: (No subject) |
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srry no idea
but may be the type of input
just an idea
8) |
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Cervantes
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| Posted: Fri Mar 11, 2005 4:30 pm Post subject: (No subject) |
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Try changing
| code: |
if (ans / x) / y = (ans / x) div y then
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to
| code: |
if (ans / x) / y = (ans / x) / y then
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. |
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Sponsor
Sponsor
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person
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| Posted: Fri Mar 11, 2005 4:49 pm Post subject: (No subject) |
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| i did that so that i know that its an integer |
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Cervantes
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| Posted: Fri Mar 11, 2005 5:12 pm Post subject: (No subject) |
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So, that if statement is trying to determine whether ans / x / y is a whole number?
Lol, sorry, I really should have thought a bit about what I suggested in my above post.
Okay, what about:
| code: |
if index (realstr (ans/x/y, 0), ".") > 0 then %if ans/x/y contains no decimals
a += 1
end if
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btw, your avatar is really large. Please scale it down. |
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person
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| Posted: Fri Mar 11, 2005 6:34 pm Post subject: (No subject) |
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thanx Cervantes!!!
btw: hows this for the size of my avatar? |
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MysticVegeta
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| Posted: Fri Mar 11, 2005 9:51 pm Post subject: (No subject) |
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What are you trying to do btw?  |
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Token
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| Posted: Fri Mar 11, 2005 10:34 pm Post subject: (No subject) |
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| yah person i like this avatar better then the other ones u were experimenting with today |
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person
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| Posted: Sat Mar 12, 2005 11:05 am Post subject: (No subject) |
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Quote: What are you trying to do btw?
ECOO #1 (it works now) |
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