patterns

[pokerface]

im trying to make a program that out puts a pattern depending of what number u input.
******************************************
var num : int

put "Enter a negative number to stop."
loop
put "How many patterns do you want? " ..
get num
exit when num <= 0
for count : 1 .. num
put "!" ..
end for
put ""
end loop
*******************************************
example of what im looking for

(if you type a 8 then u get "!@#!@#!@" as the answer but if u type 1 then u get "!" or a 9 then u get "!@#!@#$!@#") need me 2 further explain then please ask me for me to answer what i mean!

[AsianSensation]

well, I suggest a bit of a string manipulation.

declare a string variable, something like this:

code:

var symbol := "!@#$%^&*"

and instead of outputting the "!".. in your code, output a random letter of the string above.

[wtd]

Get a number of characters.
Create a counter variable, set it to 1.
Create an empty string variable to hold the output pattern.
Start a loop.
If the counter is greater than the number of characters, exit the loop.
Add "!" to the string.
Increase the counter by one.

If the counter is greater than the number of characters, exit the loop.
Add "@" to the string.
Increase the counter by one.

If the counter is greater than the number of characters, exit the loop.
Add "#" to the string.
Increase the counter by one.
End the loop.

[AsianSensation]

wait, what was the pattern?

like if I input 1, it out puts "!"
2 and "!@"
3 and "!@#"
4 and "!@#$" or something?

but 8 was "!@#!@#!@", so it was taken in groups of 3s
and 9 was "!@#!@#$!@" which was weird because it had 10 chars and weird repeating patterns.

I suggest a further explaination.

[pokerface]

i want it to put ! if the user asked to put 1 symbol
but !@ if the user asked for 2 symbols.
its werid but i want it to add # if they ask for 3 symbols!!!


*****************************************
How many patterns do you want? 1
!
How many patterns do you want? 2
!@
How many patterns do you want? 3
!@#
How many patterns do you want? 4
!@#!
How many patterns do you want? 5
!@#!@
How many patterns do you want? 6
!@#!@#
How many patterns do you want? 7
!@#!@#!
********************************************

You get what i mean?

[wtd]

pokerface wrote:

You get what i mean?

The algorithm I provided does exactly what you want.

[pokerface]

sorry that was directed to AsianSensation

[wtd]

I know. Just seemed kind of odd that you were still fishing when I'd thrown out a way of getting it done.

[AsianSensation]

yah, I was confused about the

Quote:

a 9 then u get "!@#!@#$!@#"

I didn't see where the "$" came from.

[pokerface]

wtd i dont understand! could u show me an example? dont worry this is not for school! i just wanted to make a pattern cause a question for school is very simular!

[AsianSensation]

I guess something like this:

code:

var symbol := "!@#" var num : int get num for rep : 1 .. num     if rep mod 3 not= 0 then         put symbol (rep mod 3) ..     else         put symbol (3) ..     end if end for

[pokerface]

ty
for ur time!

[wtd]

pokerface wrote:

wtd i dont understand! could u show me an example? dont worry this is not for school! i just wanted to make a pattern cause a question for school is very simular!

I won't show you in Turing, because then you could just copy and paste.

[code]# get an integer representing the number of characters
num_chars = gets.to_i

counter = 1

output = ""

loop do
break if counter > num_chars
output += "!"
counter += 1

break if counter > num_chars
output += "@"
counter += 1

break if counter > num_chars
output += "#"
counter += 1
end loop

puts output

[Andy]

wtd wrote:

I won't show you in Turing, because then you could just copy and paste.

i thought it was cuz u dont have turing on ur comp lol

[wtd]

dodge_tomahawk wrote:

wtd wrote:

I won't show you in Turing, because then you could just copy and paste.

i thought it was cuz u dont have turing on ur comp lol

For something this simple, I can manage to write code that would work.