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 Decimal > Binary
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Blade




PostPosted: Mon Apr 07, 2003 8:15 pm   Post subject: Decimal > Binary

for school i'm supossed to make a program that converts decimal to binary... and vice versa... could someone suggest a method to do this?
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void




PostPosted: Mon Apr 07, 2003 8:33 pm   Post subject: (No subject)

i'd use a loop to check to see what the largest power of two is that can go into the enterd number....(like if num_entered <2**a(where a is now 5) then largest_power:=a-1..end if and exit loop) and then its simple to just chek, display a 1 or 0 and subtract....as for the binary to decimal...well...try loading the number as a string...then doing a check on it...find out how many numbers are in it...thats the largest power of two to multiply by...then you use a for a:1..lenght(binary_number) and check for what place all the ones are in and while your doing that....every time there is a one..then decimal_number:=decimal_number+2**a other wise do the hokey pokey Razz) i hope that helps you some what..
Dan




PostPosted: Mon Apr 07, 2003 11:48 pm   Post subject: (No subject)

DAN'S CHEP WAY OF BASE COVERSION

code:

var num: int

put "put  in  a  num: "..
get num
put ""
put intstr(num,0,2)


the intstr comand can cahge the base of the int being sent in to it. in thiis case it chages it to a base of 2 or binaey.

this method whode not be good for a school progject becuse it is not grat progaming and techers dont like it becuse it dose not giive them a lot to mark Laughing

for more help on intstr look it up in help in turing...
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Asok




PostPosted: Mon Apr 07, 2003 11:54 pm   Post subject: (No subject)

dan you owned that assignment! Smile
Prince




PostPosted: Tue Apr 08, 2003 9:52 am   Post subject: (No subject)

heres how i did it

code:

function getBinary : int
    var bin_num : int
    loop
        cls
        put "Enter a number in binary form -> " ..
        get bin_num
        exit when bin_num >= 0
    end loop
    result bin_num
end getBinary

% ---------- Main ----------

var binary, decimal, digit, temp, x, sum, ibinary : int
sum := 0
x := 1

binary := getBinary
ibinary := binary

loop
    digit := binary mod 10
    binary := binary div 10
    temp := digit * x
    x := x * 2
    sum := sum + temp
    exit when binary = 0
end loop

put ""
put "The decimal equivalent of ", ibinary, " is ", sum


complete with a function Very Happy (impressive isnt it.. lol)
Blade




PostPosted: Tue Apr 08, 2003 11:00 am   Post subject: (No subject)

lol, yea... thx... whats the loop for in the function?
Asok




PostPosted: Tue Apr 08, 2003 11:01 am   Post subject: (No subject)

because it handles it one digit at a time so it needs to loop it
Prince




PostPosted: Tue Apr 08, 2003 5:32 pm   Post subject: (No subject)

well actually the one in the function jus makes sure that no idiots run it a start typin away negative numbers (tho i now realize there r idiots who'll enter non-binary numbers Shocked )... but good job on explainin the second loop asok
Asok




PostPosted: Tue Apr 08, 2003 11:59 pm   Post subject: (No subject)

ohh... the loop IN the function. meh, I'm tired.
Blade




PostPosted: Wed Apr 09, 2003 12:16 am   Post subject: (No subject)

i honestly didnt think there would be anyone stupid enough to try to do that.... (enter negitive numbers)... but anotheer way to handle it would be to use natural variables...
Asok




PostPosted: Wed Apr 09, 2003 12:50 am   Post subject: (No subject)

well technically -101 is still the binary equivalent of -5 so you can get negative numbers in binary
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