shifting number in an array

[sammi]

What is it you are trying to achieve?
<Make the first number 68 and get the rest of the numbers in my partially filled array to shift to the right>


What is the problem you are having?
<Can only get 2 of the number the move and the rest stay the same>


Describe what you have tried to solve this problem
<Answer Here>


Post any relevant code (You may choose to attach the file instead of posting the code if it is too long)
<Answer Here>

Turing:

% Add the value 68 at the start of the filled section % shifting everything else to the right % and adjust variables so it will actually print % % Example % Before: [1][2][3][4] % After:  [68][1][2][3][4] var numSlots : int numSlots := Rand.Int(8,14) var numElements : int numElements := Rand.Int (3,7) var nums : array 1 .. numSlots of int for i : 1 .. numElements     nums (i) := Rand.Int (10, 99) end for % Print Array (all on one line) for i : 1 .. numElements     put "[", nums (i), "]" .. end for put ""  % so it goes to a new line % YOUR CODE HERE var firstSlot : int := nums(1) var thirdSlot : int := nums (3) for i : 1 .. numElements nums (1) := 68 nums (2) := firstSlot nums (3) := nums (4) end for % Print array again for i : 1 .. numElements     put "[", nums (i), "]" .. end for put ""

Please specify what version of Turing you are using
<Answer Here>

[Insectoid]

Quote:

Can only get 2 of the number the move and the rest stay the same

Maybe if you do this often enough, all of them will have moved.

[Tony]

adding elements to the beginning of an array is incredibly expensive (performance) and complicated (shifting all the other elements). Why would you want to do this?

E.g. you can add the element at the end

code:

before: [4][3][2][1] after: [4][3][2][1][68]

All the elements preserve the same relative order as in your example, but the insert doesn't require any shifting of elements.

[Beastinonyou]

However, If you really need to do it like that, you could use something as simple as this:

Turing:

var nums : flexible array 1 .. 0 of int for i : 1 .. 4     new nums, upper (nums) + 1  % Creates new place in array 'nums'     nums (i) := i %Rand.Int (10, 99), I'm using 'i' to make it appear how you wanted end for % Display the original values in array 'nums' for i : 1 .. upper (nums)     put "[", nums (i), "]" .. end for put "" % _____ Pay Attention Below _____ new nums, upper (nums) + 1 % Create new place in array for decreasing i : upper (nums) .. 2 % Go from the end, to 2nd spot     nums (i) := nums (i - 1)    % Value becomes the value previous to it's spot in array end for nums (1) := 68  % Change first spot in array to 68, as you wanted % Display array, which now has 68 in first spot, and the rest of the values after for i : 1 .. upper (nums)     put "[", nums (i), "]" .. end for

[sammi]

now im getting some error message that says "variable has no value" but i declared it above so i dont know what this means

Turing:

% Add the value 68 at the start of the filled section % shifting everything else to the right % and adjust variables so it will actually print % % Example % Before: [1][2][3][4] % After:  [68][1][2][3][4] var numSlots : int numSlots := Rand.Int (8, 14) var numElements : int numElements := Rand.Int (3, 7) var nums : flexible array 1 .. numSlots of int for i : 1 .. 4     new nums, upper (nums) + 1  % Creates new place in array 'nums'     nums (i) := i % Using 'i' to make it appear how I wanted end for % Display the original values in array 'nums' for i : 1 .. upper (nums)     put "[", nums (i), "]" .. end for put "" % YOUR CODE HERE new nums, upper (nums) + 1 % Create new place in array for decreasing i : upper (nums) .. 2 % Go from the end, to 2nd spot     nums (i) := nums (i - 1)    % Value becomes the value previous to it's spot in array end for nums (1) := 68  % Change first spot in array to 68 % Display array, which now has 68 in first spot, and the rest of the values after for i : 1 .. upper (nums)     put "[", nums (i), "]" .. end for % Print array again for i : 1 .. numElements     put "[", nums (i), "]" .. end for put ""

[Insectoid]

"variable has no value" means you're trying to do something with a variable that has no value yet. When you declare a variable it doesn't yet have a value.

code:

var i : int i++

This won't execute. What is i? How can I add to i, if I don't know what it is?

code:

var i : int i := 0 i++

Now we know that i is 0, so we can add to it no problem.

Now, in your code you've created an array of random length between 8 and 14. So 'upper' is at least 8. You then go on to execute a for loop 4 times, filling in the first 4 values in the array and making the array 4 spaces bigger. The array is now between 12 and 18 slots in length.

Then, you iterate over the entire array and try to output the value at each index in the array. But...we have at least 12 elements, and we only assigned 4 values. That leaves six elements with no value, that you are trying to print. And there, sir, is your error.

[sammi]

so how would i input that into my code.....????

[Beastinonyou]

This:

Turing:

var nums : flexible array 1 .. numSlots of int

Is your Problem

You're starting your array with an upper bound of 8 to 12. Then later, you're adding 4 more.

You need to start with 0.

Turing:

var nums : flexible array 1 .. 0 of int

And also, Why are you printing the array a third time?

Turing:

% Print array again for i : 1 .. numElements     put "[", nums (i), "]" .. end for put ""

fix your flexible array bounds, and run it. You'll see what I mean by the output window.

[evildaddy911]

heres a way that i figures out, you just need to have the computer know what each element is:

Turing:

var aray : array 1 .. 5 of int for i : 1 .. 5     aray (i) := i end for for j : 1 .. 5     put aray (j) end for put "" for decreasing k : 5 .. 2     aray (k) := aray (k - 1)     put aray (k) end for

then you figure out what the new aray(1) is and your all set