How can I get a variable using a variable?

[Linksku]

What is it you are trying to achieve?
I have a variable amount of variables. The variable are all flexible arrays. I wanted to use multidimensional arrays, but the second dimension isn't resizable. It's too hard to explain here, check the code.

Post any relevant code (You may choose to attach the file instead of posting the code if it is too long)
<Answer Here>

Turing:

% What I tried doing, but doesn't work % var playerx : flexible array 1 .. numplayers, 1 .. 1 of int % ... % new playerx, numplayers, turn % What I'm trying to do for i:1..numplayers var playerx+i := flexible array 1 .. 1 of int end for % Basically creates the variables playerx1, playerx2, playerx3 ...

Please specify what version of Turing you are using
4.1.1

[Zren]

Turing:

var w, h : int := 10 var grid : flexible array 1 .. 0, 1 .. 0 of int new grid, w, h % Set bounds (size)

You start out at 0, then set the size after.

Can I ask what you need this array for?

[Tony]

while the syntax allows for it, I'm not sure if that ever was actually implemented
flexible

Quote:

In the current implementation (1999), with a multi-dimensional array with a non-zero number of total elements, it is a run-time error to change any but the first dimension (unless one of the new upper bounds is one less than the corresponding lower bound, giving 0 elements in the array) as the algorithm to rearrange the element memory locations has not yet been implemented.

You _could_ have a flexible array of pointers, that point to more flexible arrays... but perhaps this can be solved with a different data-structure design.

[Raknarg]

Nope, you can definitely resize multi-dimensional arrays. I've done it in the past; they probably forgot to make it impossible.

[Linksku]

I found this: http://compsci.ca/v3/viewtopic.php?t=14333
But it seems that I can only set the second dimension's size if one of the dimensions is 0. Is there a workaround for this?

@Zren: I'm making a game, and I need to know the x and y of everywhere the players have gone. Basically keeps track of the movements of each player.

[goroyoshi]

you dont need flexible arrays for tracking movement, just use an array or two for each player

[Zren]

You'll just end up with two multidemensional arrays for x and y. That's just adding to the problem. Learn about records. They are veeeery valuable. An example in your case would be something like:

Turing:

type Move :     record         player, x, y : int     end record var moves : flexible array 1 .. 0 of Move % Register a new move new moves, upper (moves) + 1 var move : Move move.player := 1 move.x := 234 move.y := 13209

I should probably explain this more, but SC waits... Ah here we go. Check this out: http://wiki.compsci.ca/index.php?title=Turing_Records_and_Types

[Linksku]

I do use records, but I can't add flexible arrays in records.

I have a variable number of players, anywhere from 1 to 4. That's why I wanted to know if I can use a variable in a variable. So that I can do something like:

code:

for i:1..numPlayer currentPlayer:=player+i end for

It seems like the only possible solution is hardcoding. But I want to make the game as efficient as possible. My last (fully playable and mildly addicting) game was only 100 lines, formatted and without comments.

[Tony]

player+i is obviously not a valid variable name, but you could have an array of players, and address individual elements by index. E.g.

code:

currentPlayer := players(i)