GUI button.... How to do an if GUI button pressed

[nick4563]

What is it you are trying to achieve?
I want to add 1 to the value of i if my GUI Button is pressed


What is the problem you are having?
Don't know what to do for the if statement

Describe what you have tried to solve this problem
Not much I'm stumped


Post any relevant code (You may choose to attach the file instead of posting the code if it is too long)
<Answer Here>

Turing:

import GUI var NQuestion : array 1 .. 9 of string NQuestion (1) := "Question 2" var i : int i := 1 procedure NextQ     put NQuestion (i) end NextQ View.Set ("graphics:300;200,nobuttonbar ") var next_question : int := GUI.CreateButtonFull (50, 10, 0, "Next Question",     NextQ, 0, '^D', true) var quitBtn : int := GUI.CreateButton (200, 10, 0, "Quit", GUI.Quit) loop     exit when GUI.ProcessEvent end loop %if (WHAT DO I PUT HERE)     then     i += 1 end if

Please specify what version of Turing you are using
4.1.1

[TerranceN]

Your program will never reach that if statement until GUI.Quit is called. Instead you need to understand how the Turing GUI module works. The loop that has GUI.ProcessEvent in it, will check to see if any buttons are pressed, update them, draw them, etc. The only way it returns true (and therefore exits the loop) is if the GUI has quit. When you press a button, the GUI module calls the procedure you give it when you made the button. The only way to know the button has been pressed is if that procedure has been called. So basically all you have to do, is increment i in your NextQ procedure.

[nick4563]

OK i read the GUI module page and understand what you are saying now thank you my code now works great... Do you have any ideas on how to set restrictions sot hat a string variable can only be ye or no?

[Tony]

code:

if my_string = "yes" or my_string = "no" then    ...

[nick4563]

thanks got it