ASCII to binary

[Thuged_Out_G]

how do you figure out the binary value of an ASCII char/word?
i want to make a program to do this, but i cant do that until i know how to convert ASCII to binary

[Tony]

well you get the ASCII value using ord()

code:

put ord("a")

then use intstr() fucntion to convert it to binary

code:

put intstr(ord("a"),0,2)

[Thuged_Out_G]

code:

put intstr(ord("a"),0,2)

what does the ,0,2) mean? [/code]

[Tony]

0 is the length out returning value... works the same as :# after a string, so 0 will not affect the output in any way.

2 is the base to which the number is converted to. 8 will make output a hex.

[Dan]

yes tony come to dark side with me, use the intstr

just to let you know that if that is for school your teacher may not like intstr it kind of takes the calangen out of making a to any bases convertor

[Thuged_Out_G]

no its not for school, i was just interested in how it was done after i downloaded tony's one in VB, i think it was tony who did it

[santabruzer]

so that's the simple of converting to binary... . ..
i was using the div 2 and rem 2 dealy.. the same way as by hand.. now it's so simple..

[PaddyLong]

hex is base 16 .... base 8 is octal

[Tony]

for my VB one, you basically grab the ord() value of the letter and turn that number into binary.

start from 2^8 and move down. If the number is larger then or equals to 2^counter then bit is 1, subtract value from number, else bit is 0. And so on until 2^0.

[Andy]

why use rem when u can use div?

[PaddyLong]

you use the remainder because any number divided by 2 will give a remainder of 0 or 1 ... so to convert from base 10 (decimal) to base 2 (binary) you just keep dividing by two and keeping track of the remainder...
ex..
25 / 2 = 12 R 1
12 / 2 = 6 R 0
6 / 2 = 3 R 0
3 / 2 = 1 R 1
1 / 2 = 0 R 1

then you read from the bottom up and record the remainders...
so 25 base 10 = 11001 base 2

another way is to use the greatest power of 2 that's less than the number...
25-16 = 9
9 - 8 = 1
1 - 1 = 0
so this means you have the 1, 8 and 16 bits set...
11001

[Andy]

i meant to say mod