String literal ends at end of line

[Lanks]

WHAT?!?!?! can turing not handle

put "\"

if you run that it will give you an error : "String literal ends at end of line"
anyone know a workaround?

i am trying to draw a ghost using ascii and it won't place the backslashes...

[DemonWasp]

Backslashes are an escape character, meaning that the second double-quote is being interpreted as part of the string, rather than the end of the string.

code:

To get this character, use this: Char      Use (tab)     \t (return)  \n "         \" \         \\

In general, whatever character you put after a backslash is interpreted by Turing as being that literal character in the string, with the exceptions of t (tab), n (newline), and possibly r (return, but not line-feed).

What you want is put "\\" .

Edit: I should mention - this isn't a workaround. It's a feature. I'm not saying that in the sarcastic sense either, this really is a feature; it's the only way to get certain characters into strings.

[andrew.]

I know that Java does this as well. Like DemonWasp said, you can't work around it, it's built in to Turing.

[DemonWasp]

It's pretty standard; Java additionally allows for \u#### in some cases for internationalisation purposes.

[Lanks]

thanks! that will work just fine