Reversing An Array

[Jagoff]

I have a program I have to write for a class, and I have to make an array run normally, then make it run backwards.

Example:
1 2 3 4 5 6...100
-Then-
100 99 98 97 96...1

The main thing giving me problems is the array is taken from a text file saved on the drive and I have to make the elements of the text file go forwards then reverse. Any ideas?

Here's my

code:

var fin, Index, client : int  % file stream number var Lname, Fname : array 1 .. 100 of string (20) open : fin, "namelist.txt", get                 % open file for get client := 1 loop     Index := 1     get : fin, Lname (Index), Fname (Index)  % get values from file     put client, " ", Fname (Index), " ", Lname (Index)     Index += 1     client += 1     exit when hasch end loop delay (1000) close : fin

Thanks!

[CodeMonkey2000]

Why not just get the information first, then output in reverse order using a for loop. And you should use a for loop to get input.

[Zeroth]

What he means is you should load all the stuff into an array first, then output it forwards and backwards.

[Jagoff]

The information I'm getting from the text file has multiple lines, and I need to read each one separately and apply a number to each one.

This is what my teacher wants:

1 ExampleI
2 ExampleII
3 ExampleIII
4 ExampleIV
5 ExampleV

-then-

5 ExampleV
4 ExampleIV
3 ExampleIII
2 ExampleII
1 ExampleI


But every examplex is a line from the file. Which there is two arrays for a First name and Last name. If it's hard to understand what I mean I'll explain it more in depth, I'm bad at explaining. :]

[Zeroth]

Look at what I wrote. Thats how you do it. The numbers can be outputted dynamically.

[Insectoid]

Load them into arrays. Use a for loop to display forwards. Use a reverse for loop to display backwards.

reverse for loop:

code:

for decreasing x: 10..1     %do stuff end for

Here's a hint: the 'x' int the for loop can be substituted into the index/subscript of the array.

[Nova]

If you really want to reverse the array, you'll need to do some juggling.
You'll need a temporary location to store a value and have a for loop in the following manner
Not exact, I haven't checked if the code is perfect, but its this kind of idea

code:

var temp : int var yourArray : array 1..* of int /pretend its already got all its values loaded/ for decreasing i : upper(yourArray)..upper(yourArray div 2)     temp := yourArray(i)     yourArray(upper(yourArray)-i)+1 := yourArray(i)     yourArray := temp end for

[S_Grimm]

a reverse array can be made with
for decreasing.