Array Addition

[Fashoomp]

I have an array thats 1..30, and all 30 contain numbers
I want another array to store the results of addition within the array.

I want addition_array (i) := num_array (i) + num_array (i+1)
Problem is for the final value, (i+1) is out of range.

[syntax_error]

trace though your program :L

you will see that the reason why you get out of range is you are looking for the 31st index; doesnt exist.

I do that that is your problem.

[Tony]

well if your range is up to 30 and you want i + 1 to be the final value, what should i go up to? that is:

i + 1 = 30
i = ?

[OneOffDriveByPoster]

So... your addition_array has one less entry, or you assume that the missing value is 0, or that the source array is circular, etc.

[Fashoomp]

That doesn't help, since my code is (i+1) - (i)

I need to subtract value 2 from 1, then 3 from 2, then 4 from 3, etc.

The array of 30 was just an example. My array size is actually the length of a word I have entered.

[Tony]

it doesn't make a difference. Just make sure that

max_i + 1 == length_of_word

[Fashoomp]

Yes, the missing value in the addition array is a 0.

[syntax_error]

Fashoomp wrote:

Yes, the missing value in the addition array is a 0.

care to clarify?

[Fashoomp]

Tony @ Tue Feb 26, 2008 6:17 pm wrote:

it doesn't make a difference. Just make sure that

max_i + 1 == length_of_word

But thats impossible. The fact that its i+1 means that it will always exceed the value of the for loop (sorry if I never mentioned thats what I'm using)

[Tony]

hmm... really?

let word = "think"
then length_of_word := length(word)
length_of_word == 5

let max_i = length_of_word - 1
max_i == 4

max_i + 1 == length_of_word
4 + 1 == 5

QED

[Fashoomp]

Sorry for double post

Would a conditional loop be better for adding my values to the array? Since I can just tell the loop to exit at word_length - 1, so my variable + 1 is my last array value?

That sounds right so I'm gonna go with that.

[syntax_error]

glad you can think it out. Try that again next time.

[Nick]

code:

for i:2..length of word word(i)+word(i-1) end for

or

code:

for i 1..length of word + 1 word(i) + word (i+1) %this will produce an error though end for