Rand Int

[cam]

Why doesn't this work?


Rand.Int (1, 6)
if Rand.Int (1) then
put "haha"
end if

[lord_pwnerer]

code:

var number : int randint(number,1,6) if number = 1 then put"haha the number = 1" end if

Use randint instead of Rand.Int... When you use randint you can assign a variable to the number, then check what that variable was set to.

EDIT: By the way, the reason that it doesn't work is when you wrote Rand.Int the second time, it was just like calling the procedure a second time, not checking to see what the random number was. (sorry if this doesn't make any sense, I'm in a rush)

[Robert]

Rand.Int is a function...

code:

if Rand.Int(1,6) = 1 then      put "haha" end if

Always use Rand.Int instead of randint

[cam]

o thx very much

[Cervantes]

lord_pwnerer @ Sun Jan 21, 2007 3:00 pm wrote:

Use randint instead of Rand.Int... When you use randint you can assign a variable to the number, then check what that variable was set to.

Please, don't say this. It's fantastically wrong. It's so wrong, we've even got a mini tutorial to explain it. Read it, and learn!