Separation Code Help

FeZbOy · **Posted:** Tue Nov 29, 2005 8:32 am

Kay, here is what I am trying to accomplish, plus a bit of background.

In calculus, my teacher taught about different functions and stuff, which inspired me to create a turing program to help my friends and I. In creating this program, I decided I need to seperate the equation in order to find the numbers, and the operation enacted on the numbers. This is where I come to help. I have the code kinda where I can figure it out, but I am stumped.

So can any programmers help? Please?

code:

proc separate (str : string, var oper : string, var num1, num2 : int)
var reals : array 0 .. 9 of int := init (0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
var nums : array 1 .. 30 of string
for i : 1 .. 30
nums (i) := ""
end for
var Var : boolean
var p : int := 1
for i : p .. length (str)
Var := false
for l : 0 .. 9
if str (i) = intstr (reals (l)) then
nums (i) += str (i)
Var := true
exit
end if
end for
if not Var then
p := i + 1
else
p += 1
end if
end for
put nums (1)
put nums (2)
num1 := strint (nums (1))
num2 := strint (nums (2))
end separate

var oper : string
var num1, num2 : int
separate ("55x3", oper, num1, num2)

Thanks,

Corey Zerf

jamonathin · **Posted:** Wed Nov 30, 2005 1:48 pm

Hey man I didn't even see ur topic, lol. I see not too many people wanted to help yas out, so i figured I would.

It's all explained in the code, if you need any more clearence, juss ask.

code:

proc separate (str : string)
var holdNumber : string := "" %This holds the information from eq'n
var oper : flexible array 1 .. 0 of string %Operations Variable - Notice we start at 0
var nums : flexible array 1 .. 0 of int %Numbers Variable
for i : 1 .. length (str) %Checking the entire length of the eq'n
if strintok (str (i)) then %If the current 'character' is a whole number
holdNumber += str (i) %Since it's a int#, add the STRING value to hold
else %if its not a whole number (i.e. decimal/operation)
new oper, upper (oper) + 1 %Make a new operation variable (started at 0)
new nums, upper (nums) + 1 %Make a new number variable (started at 0)
% It's the current character thats not a whole number so make . .
oper (upper (oper)) := str (i) % . . oper equal to that
nums (upper (nums)) := strint (holdNumber) %Give the held number to nums
holdNumber := "" %Start holdNumber, over
end if
end for

% if we dont put this in, the eq'n (55x3) will result in (55x) with no 3
% this is because we have mroe numbers than operators (by 1)
new nums, upper (nums) + 1 %So make one more
nums (upper (nums)) := strint (holdNumber) %make it equal to whatever was last saved

% D I S P L A Y I N G
% we go up to the max number of 'oper' because if we went to the max of nums,
% there would be one too many for oper, therefore program crashes
for i : 1 .. upper (oper) %Showing spaces to provd we've seperated
put nums (i), " ", oper (i), " " ..
end for
% Since there's one more, show it!
put nums (upper (nums))

%Showing more seperation (\n is same as: put "")
put "\n\n\nOperations in Equation:"
put "-----------------------"
for i : 1 .. upper (oper)
put oper (i)
end for
put "\nNumbers in Equation"
put "-------------------"
for i : 1 .. upper (nums)
put nums (i)
end for

end separate

separate ("55x3+55522342-5*2/6=10")

% Enjoy.

ZeroPaladn · **Posted:** Thu Dec 01, 2005 9:59 am

i would have posted, if i understood what he was trying to dowith tat program :\

jamonathin · **Posted:** Thu Dec 01, 2005 11:48 am

ZeroPaladn wrote:

i would have posted, if i understood what he was trying to dowith tat program :\

Separation Code - seperate code Razz

.

Me to oactually, i had to read it acouple times. He said he was in calculus so i figured his equation was 55x^3 (cubed) and he was going to be taking the derivitve. I guess he still can tho with that code. Confused

FeZbOy · **Posted:** Tue Dec 06, 2005 11:24 am

Sweet, Thx

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