Quadratic Trinomials

[Token]

Hey everyone, I just recently got fed up with the ammount of homework my math teacher has been giving my class, its not that its hard but that there is so much of it, she'd give us around 30 questions just solving quadratic trinomials (a²+b+c) to do at home, on top of whatever other little tidbits she had taught us today, so0o i figured i'm not gonna do all that work and i made a program to solve quadratic trinomials for you, it still might be a little buggy, if you find one pm me or post it here. Enjoy!

heres an question to try it out on X²+2X-15

code:

var digit1, digit2, counter, sum, prod, i, done, a, b, c, common1, common2 : int var x : string setscreen ("text:max;max") loop     put "Enter the value for.."     put "\tA: " ..     get a     put "\tB: " ..     get b     put "\tC: " ..     get c     put "What letter would you like to use as a variable? " ..     get x     if a = 1 then         put "\n\t", x, chr (178), "+", b, x, "+", c     else         put "\n\t", a, x, chr (178), "+", b, x, "+", c     end if     sum := b     prod := a * c     done := 0     counter := -100     loop         i := -101         loop             i := i + 1             if counter * i = prod and counter + i = sum then                 put "\nProd: ", prod, " = ", counter, " x ", i                 put "Sum: ", sum, " = ", counter, " + ", i                 done := 1             end if             exit when i = 100 or done = 1         end loop         exit when done = 1         counter := counter + 1     end loop     if a = 1 then         put "\n(", x, chr (178), "+", i, x, ") (", counter, x, "+", c, ")"     else         put "\n(", a, x, chr (178), "+", i, x, ") (", counter, x, "+", c, ")"     end if     put "What is common in the first part of the equation?(besides ", x, ")if nothing enter 1 " ..     get common1     put "The seccond? " ..     get common2     if a = 1 then         put "\n", x, chr (178), "+", b, x, "+", c     else         put "\n", a, x, chr (178), "+", b, x, "+", c     end if     if a = 1 then         put "(", x, chr (178), "+", i, x, ") (", counter, x, "+", c, ")"     else         put "(", a, x, chr (178), "+", i, x, ") (", counter, x, "+", c, ")"     end if     if common1 = 1 and a = 1 and counter / common2 = 1 then         put x, "(", x, "+", i / common1, ")+", common2, "(", x, "+", c / common2, ")"         put "(", x, "+", i / common1, ")(", x, "+", common2, ")"     elsif common1 = a then         put common1, x, "(", x, "+", i / common1, ")+", common2, "(", counter / common2, x, "+", c / common2, ")"         put "(", common1, x, "+", i / common1, ")(", common1, x, "+", common2, ")"     elsif common1 = 1 and a = 1 then         put x, "(", x, "+", i / common1, ")+", common2, "(", counter / common2, x, "+", c / common2, ")"         put "(", x, "+", i / common1, ")(", common1, x, "+", common2, ")"     elsif common2 = 1 and a = 1 then         put x, "(", x, "+", i / common1, ")+", common2, "(", counter / common2, x, "+", c / common2, ")"         put "(", x, "+", i / common1, ")(", common1, x, "+", common2, ")"     elsif common1 = 1 then         put x, "(", a / common1, x, "+", i / common1, ")+", common2, "(", counter / common2, x, "+", c / common2, ")"         put "(", a / common1, x, "+", i / common1, ")(", common1, x, "+", common2, ")"     else         put common1, x, "(", a / common1, x, "+", i / common1, ")+", common2, "(", counter / common2, x, "+", c / common2, ")"         put "(", a / common1, x, "+", i / common1, ")(", common1, x, "+", common2, ")\n\n\n"     end if     delay (1000)     loop         exit when hasch     end loop end loop

Edit: I cleaned up the code a bit, changed the screen to text, and made the output more user friendly

[jamonathin]

pretty good! I juss think your next step is to figure it out using the quadratic formula, incase it doesn't work out perfectly, which shouldn't be too hard to do, other than that, gj.

[Token]

thanks man, yah i would but thats the only way she has showed us how to do it, she said she was gonna show us the other way when we get back from the march break, but my school is desemestered and we run on a day 1 day 2 schedual so we learn things over a more spread out period of time, thats why she hasnt showed us yet

thanks for the feedback!

[jamonathin]

here i juss show you the formula

x = -b +- sqrt[b**2 - 4(a)(c)] all divided by 2(a)

[Token]

okay so let me try one to se if i get it

x = -b +- sqrt[b**2 - 4(a)(c)] all divided by 2(a)

i'll use the example i gave above... X²+2X-15
a= 1
b= 2
c= (-15)

= -2+ - sqrt (2² x 2- 4 (1)(-15) ) /2
= -2+ - sqrt (8-(-60)) /2
= -2+ - sqrt (68 ) /2
= -2+ (-8.25) /2
= -10.25 /2
= -5.125

some how i dont think that turned out right... lmao... help

okay the questions i have are
- by **2 do you mean ² ? because what i did was squared it and then multiplied it by 2... maybe thats my problem, if not let me know, thanks
and if i'm starting to bug one of the mods just let us know and we can do this through pm

[person]

-b (+ or -) squaroot (b^2 - 4ac) all div 2a should work

ur not getting it (theres sometimes 2 solutions??)

[Token]

= -2+ - sqrt (2² x 2- 4 (1)(-15) ) /2
= -2+ - sqrt (8-(-60)) /2
= -2+ - sqrt (68 ) /2
= -2+ 8.25 /2 or = -2 -8.25 /2
= 6.25 / 2 = -10.25 /2
= 3.15 = -5.125


i think i get it now, but i think i got the wrong answer... somehow lol but yes i realise now that +- meant +/- because a parabola has to roots, or x-intercepts, but i think i screwed up my answer somewehere here '(2² x 2' umm do u see my problem? thanks

[person]

y do u have 2^2 * 2?? its supposed to be 2^2 not 2^3

im so happy i can help someone whos probably in a higher grade than me (gr9)

[Token]

= -2 +/- sqrt (2² - 4 (1)(-15) ) /2
= -2 +/- sqrt (4 - (-60)
= -2 +/- sqrt (64)
= -2 + 6 or = -2 - 6
= 4 or = -8


... okay but what are 4 and -8? the roots? if they are then i did some calculations wrong because when i solved this with x=a²+b+c i got the roots to be -5 and 3

and yes you are helping somone older than you

[[Gandalf]]

WTF? You're doing this in grade 9?

All I did in grade 9 is a**2 + b + c using decomposition, and then special cases and stuff like that.

If you still don't understand the symbols or what to do:

[Token]

AHH Gandalf you did it lol i get it now, so it would go like this

X= (-b +/- sqrt (b² - 4ac) ) /2a
X= (-2 +/- sqrt (2² - 4(1)(-15) ) ) /2
X= (-2 +/- sqrt (4 - 4(-15) ) ) /2
X= (-2 +/- sqrt (4 - 4(-15) ) ) /2
X= (-2 +/- sqrt (4 + 60 ) ) /2
X= (-2 +/- sqrt (64) ) /2
X= (-2 +/- 8 ) /2

X= (-2 + 8 ) /2
X= 6/2
X= 3

X= -10 /2
X= -5

YAY! I GOT IT!! lol i'm gonna suprise the hell out of my math teacher tommorow! thanks guys
btw my error b4 was i pulled a brain fart on the sqrt of 64

[Token]

So this would be the code to figure it out through the equation

code:

var a, b, c : int loop put "Enter the value for.." put "\tA: " .. get a put "\tB: " .. get b put "\tC: " .. get c put "= (-b +/- sqrt ((b) - 4 * a * c)) / 2 * a" put "= (-", b, "+/- sqrt ((", b, chr (178), " ) - 4 * ", a, "*", c, ")) / 2 *", a put "= (", -b, "+/- sqrt ((", b * b, " ) - ", 4 * a * c, ")) / ", 2 * a put "= (", -b, " +/- ", sqrt ((b * b) - 4 * a * c), ") / ", 2 * a put "\n= (", -b, " +", sqrt ((b * b) - 4 * a * c), ") / ", 2 * a put "= (", -b + sqrt ((b * b) - 4 * a * c), ") / ", 2 * a put "= ", (-b + sqrt ((b * b) - 4 * a * c)) / 2 * a put "\nor" put "\n= (", -b, " -", sqrt ((b * b) - 4 * a * c), ") / ", 2 * a put "= (", -b - sqrt ((b * b) - 4 * a * c), ") / ", 2 * a put "= ", (-b - sqrt ((b * b) - 4 * a * c)) / 2 * a put "\n\nPress any key to do another" loop exit when hasch end loop end loop

[person]

i never said i was learnig this in grade 9...frankly my class hasnt even touched anything to the power of 2 wich is sad becasue im in a program that is supposed to be for ppl who r good at Math, Computers, and Science

[cool dude]

nice prog but it's useless to me for now. we didn't learn this stuff in math yet, but i know we will be learning this in this semester because we r doing similar stuff right now.

school programs r really bad, they should be teaching this stuff in earlier grades instead of teaching us +-x/ for several years.

[endusto]

if there are no real roots you get an error.