String does not contain?

[Donny]

if (button == right && msg.contains(k));

I have this in an if statement, now i want something that will check for anything but that, how can this be achieved?

[Tony]

http://en.wikipedia.org/wiki/De_Morgan's_laws

[Donny]

This isn't a school project or anything so a little actual advice would help, I don't feel like reading this whole article. It doesn't even have code snippets.


EDIT: sorry for my rudeness and stupidity, i'm ill and not in a good mood, i just figured it out.. != infront instead of &&..

[Tony]

It's was like the very first thing on the page

Quote:

NOT (P AND Q) = (NOT P) OR (NOT Q)

P := button == right
Q := msg.contains(k)

so you want

code:

if ( button != right || !msg.contains(k) )

You could also just negate the entire statement

code:

if (!(button == right && msg.contains(k)))

P.S. figuring out how stuff works well enough to write good programs requires a lot of reading.

[Donny]

Ya, i figured as much I just wasn't in the mood, and the way I did it didn't work out, instead of && i put != when I didn't know you could just put ! to negate something, and it would move my chars (over a network) in opposite directions somehow lol


EDIT: Also, how can i trim strings? I want to take 59021 : right and trim it down to just 59021, do you know how to do this?

[SmokeMonster]

Use the trim function. http://download.oracle.com/javase/1.3/docs/api/java/lang/String.html#trim%28%29

[Insectoid]

That's not exactly what he was going for.

Use a string tokenizer. I dunno how it works in Java, but it certainly exists. Use a colon (Or, a space followed by a colon) as the delimiter and take the first token.

[Tony]

Insectoid @ Thu Apr 21, 2011 9:45 am wrote:

Use a string tokenizer. I dunno how it works in Java

Java's Scanner class can take a custom delimiter and tokenize the input.