deltatux
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 Posted: Tue Apr 07, 2009 9:13 pm Post subject: [JavaScript] Sliding Tile Game ... help? |
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Hey guys,
I really need some help here and I'd appreciate if you guys can help me.
Alright, so I'm suppose to design a sliding tiles game. However, if you play around with it, it obviously doesn't work as you can see:
URL: http://matrix.senecac.on.ca/~akwok9/bti220/assign3/
To replicate the bug above, all you need to do is to start playing from bottom up and then the tiles starts disappearing.
Also, another issue is that I don't quite know how to tackle checking when you win. I understand that it must match 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15. Can you give me a hint? My implementation is definitely flawed and is shown in the code below.
| code: |
<script type="text/javascript">
//<![CDATA[
var rows = new Array(4)
rows[0] = new Array (4)
rows[1] = new Array (4)
rows[2] = new Array (4)
rows[3] = new Array (4)
function checkWin() {
var winner = false
var checker = new Array(4)
checker[0] = new Array (1, 2, 3, 4)
checker[1] = new Array (5, 6, 7, 8)
checker[2] = new Array (9, 10, 11, 12)
checker[3] = new Array (13, 14, 15, 0)
for (i = 0; i < 4; i++){
for (j = 0; j < 4; j++){
if (rows[i][j] == checker[i][j]){
winner = true
}
}
}
if (winner){
alert("Congratulations! You've Won!")
return true
}
return false
}
function move(tile){
var obj = document.getElementById('tile' + tile)
var win = false
for (i = 0; i < 4; i++){
for (j = 0; j < 4; j++){
if (rows[i][j] == tile){
if (j > 0 && rows[i][j - 1] == 0){
obj.style.left = (j - 2) * 100 + 'px'
rows[i][j - 1] = tile
rows[i][j] = 0
}else if (j < 3 && rows[i][j + 1] == 0){
obj.style.left = (j + 2) * 100 + 'px'
rows[i][j + 1] = tile
rows[i][j] = 0
}else if (i > 0 && rows[i - 1][j] == 0){
obj.style.top = (i - 2) * 100 + 'px'
rows[i - 1][j] = tile
rows[i][j] = 0
}else if (i < 3 && rows[i + 1][j] == 0){
obj.style.top = (i + 2) * 100 + 'px'
rows[i + 1][j] = tile
rows[i][j] = 0
}
win = checkWin()
if (win){
break
}
return
}
}
}
}
function initialize(){
var check = new Array (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15)
for (i = 0; i < 4; i++) {
for (j = 0; j < 4; j++) {
if (i == 3 && j == 3){
rows[i][j] = 0
} else {
var n = Math.ceil(Math.random() * 15)
while (check[n - 1] == 0){
n = Math.ceil(Math.random() * 15)
}
rows[i][j] = n
check[n - 1] = 0
document.getElementById('tile' + n).style.left = (j + 1) * 100 + 'px'
document.getElementById('tile' + n).style.top = (i + 1) * 100 + 'px'
}
}
}
}
// ]]>
</script>
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Many thanks,
deltatux |
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