A riddle!?

[TokenHerbz]

3 men walk into a hotel for the night, They each pay 10 dollars for a room.
The 3 men go upstairs and relax in their room.
The manager over charged by 5 dollars, So he goes to return the 5 dollars to the 3 guys.
Noticing he cannot divide 5 by 3 evenly, He gives EACH man 1 dollar, and keeps 2 dollars.

So if each man paid 9 dollars for the room, since they had paid 10 and got 1 back,
and the manager kept 2, where did the other dollar go?

9 * 3 = 27 + 2 = 29 not 30.

I'll give you the answer in a week if no one gets it, but since everyone here is so smart, i shouldn't have to
Good Luck!

[octopi]

Oh the age we live in.....no longer do you have to figure things out for yourself when you can JFGI to get the answer.

[Ultrahex]

spoiler:
Well, overall their rooms were suppose to cost $25, and they got $3 dollars return, and $2 dollars pocketed, thus making $30.
Because they do not pay their refund, they pay what the manager+hotel has which is 27 overall (30-3), and they have the 3 dollars in their pockets.
Thus it is suppose to be 9*3=27+3=30, cause what they paid includes what the manager has in pocket

Very Easy

[MihaiG]

Spoiler
there is an easier way to look at it heres the math way

they each were supposed to pay for the night 25/3 (they were charged 5 dollars more for 30) per person,

now if they are each refunded one dollars

25/3 + 1/1 = 25/3 + 3/3 = 28/3

now there are 3 people

so we have (28/3)*3 + 2 that the manager kept

which is 28 + 2 = 30

[OneOffDriveByPoster]

Spoiler:

Quote: So if each man paid 9 dollars for the room, since they had paid 10 and got 1 back, and the manager kept 2, where did the other dollar go? 9 * 3 = 27 + 2 = 29 not 30. They did not pay $9 for the room. The truth is that they paid $25/3 for the room and $2/3 of the $2 that the manager has. The equation is 25/3*3 + 2/3*3 = 27. Where did the other 3 dollars go? They got it back--$1 each.