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 array out of bounds
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cool dude




PostPosted: Wed Jul 26, 2006 2:01 pm   Post subject: array out of bounds

i made this sample program test however i'm getting an array out of bounds error and i can't seem to fix it.

code:

import java.math.*;

public class Problem25 {
        public static void main (String[] args) {
                BigInteger[] num = new BigInteger[2];
                               
                for (int i = 0; i < 3; i++) {
                        if (i == 0) {
                                num[0] = BigInteger.valueOf(1);
                        }
                        if (i == 1) {
                                num[1] = BigInteger.valueOf(1);
                        }
                        else {
                                num[i] = num[i-1].add(num[i-2]);               
                        }
                }
                System.out.println(num[2]);
        }
}
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rizzix




PostPosted: Wed Jul 26, 2006 2:30 pm   Post subject: (No subject)

code:
      BigInteger[] num = new BigInteger[3];


3 not 2. It's the length not the last index.
[Gandalf]




PostPosted: Wed Jul 26, 2006 3:53 pm   Post subject: (No subject)

So to prevent things like this from happening in the future, use num.length instead of a constant number which really has nothing to do with your array. The loop would become:
code:
for (int i = 0; i < num.length; i++) ...


Though this brings up the question of... Do you not understand arrays yet, or did you simply overlook this? Arrays are much more important to understand than BigIntegers.
cool dude




PostPosted: Thu Jul 27, 2006 11:09 am   Post subject: (No subject)

thanks. one more question. how would you get the length of the number of digits in the array. for example if the number was 1234 it would tell me that its 4 digits long. i tried using lenght(); but it doesn't work. it says, "cannot resolve symbol method length()"
cool dude




PostPosted: Thu Jul 27, 2006 11:23 am   Post subject: (No subject)

here's my code:

code:
import java.math.*;

public class Problem25 {
        public static void main (String[] args) {
                BigInteger[] num = new BigInteger[7];
               
                num[0] = BigInteger.ONE;
                num[1] = BigInteger.ONE;
                for (int i = 2; i < num.length; i++) {
                        num[i] = num[i-1].add(num[i-2]);
                        if (length(num[i]) >= 2) {
                                System.out.println(num[i]);          
                        }
                }
        }
}
wtd




PostPosted: Thu Jul 27, 2006 11:42 am   Post subject: (No subject)

Where does the method "length" come from?
cool dude




PostPosted: Thu Jul 27, 2006 12:08 pm   Post subject: (No subject)

wtd wrote:
Where does the method "length" come from?


what do you mean where it comes from? i've always been able to do something like :
code:
num.length();
but because this is an array i can't do it the same way i'm guessing.
wtd




PostPosted: Thu Jul 27, 2006 12:24 pm   Post subject: (No subject)

Back to Java 101.

All methods live inside classes. Which class does the length method live in?
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cool dude




PostPosted: Thu Jul 27, 2006 12:34 pm   Post subject: (No subject)

wtd wrote:
Back to Java 101.

All methods live inside classes. Which class does the length method live in?


oh i see. the string class. so now i have to convert the array to a string. but how?
cool dude




PostPosted: Thu Jul 27, 2006 1:03 pm   Post subject: (No subject)

just figured it out. thanks for the help Smile
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