Addition of Digits in integer

[Caceres]

Hello, I was just wondeirng how to add the digits of an integer.

For example:

code:

private static int sumofbinumbers(String sin) { two=(sin.charAt(1)-48)*2 four=(sin.charAt(3)-48)*2 six=(sin.charAt(5)-48)*2 eight=(sin.charAt(7)-48)*2                 sum_two=(two.charAt(0)) + (two.charAt(1)) sum_four=(four.charAt(0)) + (four.charAt(1)) sum_six=(six.charAt(0)) + (six.charAt(1)) sum_eight=(eight.charAt(0)) + (eight.charAt(1))

I'm basically curious into how to add up the sums of digits of an integer.
I wa wondering if the sum_two and the part to follow will work.
Would i have to put int two = (sin.charAt(1)-48)*2.
Thanks.
P.S Sorry if this is unclear
~Caceres

[wtd]

There's a mathematical way of doing this. Since I don't like just giving out easy answers...

code:

(define (sum-digits n)   (if (= n 0)       0       (+ (remainder n 10)          (sum-digits (floor (/ n 10))))))

[Caceres]

For my previous code. It keeps saying

Quote:

int cannot be dereference

Anyone know what this means?

[Caceres]

For my previous code. It keeps saying

Quote:

int cannot be dereference

Anyone know what this means?

[[Gandalf]]

It means that an int is not an object, and therefore cannot be treated as such. An Integer, however...