large counted loop

[cool dude]

if you have to go to a very large number in a counted loop, it will say integer too large. so how would i do that? i tried using BigInteger, but it is not working and i'm not too sure if that is right?

[r.3volved]

counted loop as in a 'for' loop??

long myNum = 0;
while(myNum != 623456823746L)
{
++myNum;
}


if it's so long that it won't let you do a for loop, then a forloop probably isn't the best aproach

[cool dude]

r.3volved wrote:

counted loop as in a 'for' loop??

long myNum = 0;
while(myNum != 623456823746L)
{
++myNum;
}


if it's so long that it won't let you do a for loop, then a forloop probably isn't the best aproach

yes counted loop as a for loop. and i need the for loop.

p.s. why do you have a L at the end of the number?

[TheFerret]

You could have a different variable type in the counter if needed, like:

Java:

for(long i=0; i<584846484654; i++) { }

And that should work...

[r.3volved]

L denotes a long integer
Just as if you were to do:

float myNum = 0.0f; //can use 'f' or 'F'


instantiation I guess would be:
long myNum = 0L; //can use 'l' or 'L'


I'd imagine the long would work with no problems in a for loop.
I just tend to avoid for loops that are so long like that and choose another procedure.

[Krabjuice]

Java:

for(int i=0; i<...; i++) {    if (i=...)    {        x+=1;    }    else if (x=...)    {        break;    } }

Replace "..." as necissary.

That should last a good while.

[wtd]

Using the assignment operator in a conditional could lead to trouble.