Programming C, C++, Java, PHP, Ruby, Turing, VB
Computer Science Canada 
Programming C, C++, Java, PHP, Ruby, Turing, VB  

Username:   Password: 
 RegisterRegister   
 Chaging around mehtods
Index -> Programming, Java -> Java Help
View previous topic Printable versionDownload TopicSubscribe to this topicPrivate MessagesRefresh page View next topic
Author Message
lain




PostPosted: Mon May 16, 2005 5:36 pm   Post subject: Chaging around mehtods

i have two mehtods (see below) that i need to convert in to two new methods; int findX(float lat, float long) and int findY(float lat, float long). Any help whould be gr8.

code:

private static float northPoalX = (float)297, northPoalY = (float)4.6496;
private static float centerX = (float)300, centerY = (float)-88;
private static float mNum = (float)7.1117;

private float distance(float x1, float y1, float x2, float y2)
{
        return (float)Math.sqrt((float)((float)Math.pow((float)((float)x2-x1),2) + (float)Math.pow((float)((float)y2-y1),2)));
}
       
private float distanceNorth(int x, int y)
{
        float dist = (float)Math.sqrt((float)((float)Math.pow((float)((float)x-northPoalX),2) + (float)Math.pow((float)((float)y-northPoalY),2)));
        return dist;
}

private float findLat(int x, int y)
{
        if (y > 217)
                return (float)90-(float)(distanceNorth((x + (int)(0.2*(northPoalX-x))), (y + (int)(0.05*(217-y)))) / mNum);
        else
                return (float)90-(float)(distanceNorth((x + (int)(0.25*(northPoalX-x))), (y - (int)(-0.15*(217-y)))) / mNum);
}
       
private float findLong(int x, int y)
{              
        float k = 0;
        float d = 0;
                       
        d = (float)(-0.16*(217-y));
                       
        float midX = (float)391.88;
        float midY = (float)-88;
                       
        float A = distance(centerX,centerY,(float)x+k,(float)y+d);
        float B = distance(centerX,centerY,midX,midY);
        float C = distance((float)x+k,(float)y+d,midX,midY);
                       
        float log = (float)Math.acos((float)((Math.pow(A,2) + Math.pow(B,2) - Math.pow(C,2))/(2*A*B))) * (float)(180/Math.PI) + (float)9;
        log += 0.06*(centerX-x);
        log *= -1;
                       
        return log;
}
Sponsor
Sponsor
Sponsor
sponsor
Martin




PostPosted: Mon May 16, 2005 5:49 pm   Post subject: (No subject)

[mod:2003166863]
[/mod:2003166863]
Display posts from previous:   
   Index -> Programming, Java -> Java Help
View previous topic Tell A FriendPrintable versionDownload TopicSubscribe to this topicPrivate MessagesRefresh page View next topic

Page 1 of 1  [ 2 Posts ]
Jump to:   


Style:  
Search: