java integer output

[kk]

hi.. i have a question about java integers. It seems when i write this code to output an integer, java outputs something totally different!

code:

// The "TestInt" class. public class TestInt {     public static void main (String [] args)     {         System.out.println (01012004);         // Place your code here     } // main method } // TestInt class

it outputs 267268! Why is this???

[rizzix]

hmm well its cuz the println method takes a string as an argument

concatenate the interger with a null string to automatically convert it to string: System.out.println(1234 + "");

[Dan]

i dont think the problem is that it is not a string b/c println can take an int and some other values but rather the porblem is that 01012004 is not an int. Integersers or any numbe realy can not start with 0

for example this code works:

code:

public class tewesf {         public static void main(String args[])         {                 System.out.println(12345);         } }

and this code give somting compley diffrent:

code:

public class tewesf {         public static void main(String args[])         {                 System.out.println(012345);         } }

Alougth if you whont to out put the 0 in front rizzix way will work.

[ify]

for the numbers 1-9 you can put a zero infront and it works fine

[Dan]

for mine it only works for 1-7, odd. I whonder what java thinks the 0 means, i know that puting a 0x infront of it gives you hex, so may be just 0 is turing it to some other base?

[rizzix]

0 in front of a number is an octal number.

[Dan]

Ah, then it all makes scen now.

I new it was coverting to some base.