inheritence & overloaded operators
Author |
Message |
Imajica
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Posted: Wed Apr 14, 2004 5:17 am Post subject: inheritence & overloaded operators |
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I have to write a program using inheritence & the overloaded << operator, how do you call the base class functions output stream from the derived class?
For example, to do a print from class base via a derived class
void derived::print()
{
base::print()
}
works, the same syntax with overloaded << does not.
I am clueless on this. |
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wtd
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Posted: Fri Apr 23, 2004 7:29 pm Post subject: (No subject) |
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Operators can be called in one of two ways.
If for instance, I have a class A that overloads << for output streams, like so:
code: | #include <iostream>
class A
{
public:
friend std::ostream& operator<<(std::ostream&, const A&);
};
int main()
{
A myVar;
std::cout << myVar;
// is the same as...
operator<<(std::cout, myVar);
}
std::ostream& operator<<(std::ostream& out, const A& a)
{
return out << "hello world!";
} |
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