arrays

[AsianSensation]

it seems that I can't declare an array with a variable as it's upper bound. Even if I declare the variable to be a constant, it still won't let me declare the array.

code:

int boundry = 7; string name [boundry];

code:

const int boundry = 7; string name [boundry];

both of the above doesn't seem to work. So, is there an easy way to declare an array with unknown boundry? Right now I'm using linked lists, just wondering if there is an easier way.

[Tony]

I'm preaty sure that I've read that in C++ array size must be decleared at compile time, so you can't use variables

[AsianSensation]

so I'm stuck with linked lists? that's not remotely cool. I really don't want to make bunch of recursive functions for a small task like this....

[Catalyst]

code:

float *array; int sizeOfArray=12; array=new float[sizeOfArray]; // Do Something delete [] array;

[AsianSensation]

oh, cool, thanks Catalyst.

[Tony]

ohh flexable arrays noted

[wtd]

Well, they're sort of flexible. You can't resize them after initializing.

If you need something resizeable, you can use the vector class that's already been written.

code:

#include <vector> int main() {    std::vector<int> my_vector(boundary);    // Then, to add something onto the end...    my_vector.push_back(42); }

[Andy]

cant u just run a for loop through the subsets after the upperbound and declare them to null?

[bugzpodder]

Quote:

Even if I declare the variable to be a constant, it still won't let me declare the array.

sure it would. except what you did isnt technically a constant

try something like const int MAXSIZE=1000 or #define MAXSIZE 1000

[wtd]

bugzpodder wrote:

try something like const int MAXSIZE=1000 or #define MAXSIZE 1000

The former is the preferred method.