odd indices of an array

[Krocker]

hi, so i need to output the odd number indices of an array without using any if statments. i know that odd = 2n+1 where n is the an integer starting at 0. my trouble is getting the for loop im using to stop when all the odd indices are outputed. So far, all i get it to is before the last index or beyond the last index, giving me an out of bound error. This is my for loop so far:

code:

System.out.println ("\n\nValues at odd-numbered indices:");                 int odd = 2;                 int shiftedOddArray = 0;                                 for (int i = 0; i < (odd-1); i++){                         odd = (2*i)+1;                         shiftedOddArray = shiftedArray[odd];                         System.out.print ( shiftedOddArray + "\t");                 }

shiftedArray is the original array that i have to output every odd index. The number of indices and the numbers in the indices are all determined by the user at the begining of the program.

[Raknarg]

You don't have to use i++. THat's just a shortcut for saying add one to i. You can do whatever you want in there (I'm pretty sure)

[Tony]

anything you want, or even nothing.

code:

for(;;){    ... }

is a valid loop. At least for C, probably Java.

[Krocker]

but how would that stop when the program has gone through the number of odd indices that are possiible according tho the user specified number of indices?

[Insectoid]

How would you do it if you wanted to run through all of the indices of the array up to the user specified limit?

[Raknarg]

@Tony is that a loop that does nothing or loops infinitely?

[Insectoid]

The 2nd argument to a for loop is the exit condition. If there is no exit condition, what do you think will happen?

[Krocker]

if there isnt an exit condition, there will be an infinite loop, thats not what im looking for. Anyways, i figured it out, i simply used a while loop and said that while (odd< numberOfArray)

[C14]

Krocker @ Mon Oct 21, 2013 8:36 am wrote:

Anyways, i figured it out, i simply used a while loop and said that while (odd< numberOfArray)

Can we see your code?

[Krocker]

Heres the code that i used:

code:

System.out.println ("\n\nValues at odd-numbered indices:");                 int odd = 1; //declare and initializes variables to be used                 int shiftedOddArray = 0;                 int n = 0;                 //does through each odd indices and outputs the value in order of the shifted array by calling shiftedArray [odd] where odd is 2n+1                 while (odd <= numberOfArray-1){                         shiftedOddArray = shiftedArray[odd];                         System.out.print ( shiftedOddArray + "\t");                         n++;                         odd = (2*n)+1;                 }