Throwing exception in Java

[Panphobia]

The traditional way I would throw an exception in a method/function I would just put throws @@@@@@@@Exception, but I recently found out while coding a BFS for a sliding puzzle game that you can throw an illegal exception just by putting 0/0 here is an example

code:

return (three.indexOf(car) != -1) ? 3 : two.indexOf(car) != -1 ? 2 : 0 / 0;

now I just wanted to ask why does that throw an illegal argument exception, and nowhere on the internet could I find an answer for that. If anyone knows could you clear that up? Thanks!

[Tony]

stacktrace please.