Author 
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octopi

Posted: Sun Dec 07, 2003 10:13 pm Post subject: f(x) == f(10x) 


100 bits for someone who solves the following problem:
Find a function f(x), where f(x) is equal to f(10x) for all values of x,
The varible x must be used in the function.
example of how not to do it:
f(x) = 4
f(x) can't be 4 (because, the result would be 4 for all values of x), and x is not used in the function.
f(x) = 4+xx
NO, because when simplified you get 4, cheap bastards.
Good luck.
Any cheapory in your anwsers will result in me not giving you bits...aka stupid anwser thats not right. but I didn't cover above in my examples of how not to do it.
(like, f(x)= 0x, or f(x)= x^0)






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Mazer

Posted: Mon Dec 08, 2003 9:16 am Post subject: Re: f(x) == f(10x) 


octopi wrote: f(x)= 0x
crap!!! now i have to come up with something else!






McKenzie

Posted: Mon Dec 08, 2003 10:05 am Post subject: (No subject) 


code: 
int f(int x)
{
while(x % 10 == 0)
x = x / 10;
return x;
}







Tony

Posted: Mon Dec 08, 2003 10:13 am Post subject: (No subject) 


wait Is the question about a math function or a programming function
btw, McKenzie  since when do you have those billion bits?
and for that matter... where did half of my bits go?

Tony's programming blog. DWITE  a programming contest. 




McKenzie

Posted: Mon Dec 08, 2003 10:36 am Post subject: (No subject) 


I think it is supposed to be a math question. I thought a compsci answer was better bits...what bits?






Tony





Blade

Posted: Mon Dec 08, 2003 1:20 pm Post subject: (No subject) 


wow, how quickly topics get changed around from the initial equation..






Andy

Posted: Mon Dec 08, 2003 7:29 pm Post subject: (No subject) 


f(x)=[1/x]
take off the top bar of the square bracket. that is actually a mathematical operator, it means the largest integer smaller than the number contained.... heh that works... but only for integral values of x






AsianSensation

Posted: Mon Dec 08, 2003 7:33 pm Post subject: (No subject) 


actually that one works for every single number except for 1 itself.
[1/1] = 1, [1/10] = 0






Andy

Posted: Mon Dec 08, 2003 7:40 pm Post subject: (No subject) 


dope!
fine [1/x+1]






AsianSensation

Posted: Mon Dec 08, 2003 7:42 pm Post subject: (No subject) 


nope, still another fault.
[1/(10 + 1)] = 1, [1/(1 + 1)] = undefined
still not every single number.






Andy

Posted: Mon Dec 08, 2003 8:48 pm Post subject: (No subject) 


okok i think i actually got it...
f(x)=[(x(x/x))/x]
how about that?






Mazer

Posted: Mon Dec 08, 2003 9:07 pm Post subject: (No subject) 


hey dodge, besides the fact that f(x) != f(10x) with your function, what is f(0)?






Andy

Posted: Mon Dec 08, 2003 9:20 pm Post subject: (No subject) 


yes it does equal... sub in any value... and undefined=undefined rite?






Mazer

Posted: Mon Dec 08, 2003 9:41 pm Post subject: (No subject) 


uh... as we all know, i really suck at math, so feel free to point out my stupidity if i do something that seems incredibly n00bishly stupid.
WW wrote: f(x)=[(x(x/x))/x]
f(5) = (5  (5/5))/5
= (5  1) / 5
= 4/5
= 0.8
right?
f(50) = (50  (50/50))/50
= (50  1)/50
= 49/50
= 0.98






