converting int to string

ahmhum · **Posted:** Sun Apr 12, 2009 7:38 pm

Ok I'm trying to convert int to string and i dun know how to, so plzz help me out

here is wat im tryin to convert

Java:

/*This method allows the user to choose which style of face he/she wants for
the Death God.*/
public static void faceQuestion(int sword)
{
//Clear screens.
d.clear();
c.clear();

//String face;

//Call upon the various initial setup methods.
{
backgroundC(x,y);
backgroundForDConsole(x, y);
textBoxForTitles();
faceTitle();
constructBoxLeftSide();
constructBoxRightSide();
constructCircleLeftSide();
constructCircleRightSide();
face1stOption();
face2ndOption();
}

//Calling upon the faceConstruct method.
{
faceConstruct();

}
//Call upon the grid method.
{
grid();
}
//Ask user first question.
d.setTextBackgroundColor(Color.black);
d.println(" Please choose your Death God's face type:");
d.println("----------------------------------------------------------------------------------------------------");
d.println("* Please enter: *");
d.println("* (1) for Human Face *");
d.println("* (2) for Hollow Face *");
d.println("* (-1) to return to previous screen. *");
d.println("----------------------------------------------------------------------------------------------------");
d.print(" Please enter your choice now: ");
//Read input.
String input = d.readLine();

//Set integers.
int face=0;

/* Set up 'if' construct with try/catch to determine the
next choice of action for the user.*/
try
{
face= Integer.parseInt(input);
}

catch (NumberFormatException e)
{
//User selects defaults to invalid entry.
}

if (face==1)
{
//Calling upon the hair method.
hairQuestion(sword, face);
}

if (face==2)
{
//Calling upon the hair method.
hairQuestion(sword, face);
}
if (face==-1)
{
swordQuestion();
}
if (-1>face||face==0||face>2)
{
//Call upon invalid entry.
invalidEntry();
//Creating the loop.
faceQuestion(face);
}

} //faceQuestion method

so instead of it being face == 1 i want it to be 1A or 1B and so on
thnx in advance

Mod Edit: Remember to use syntax tags! Thanks Smile

code:

[syntax="java"]Code Here[/syntax]

Dark · **Posted:** Sun Apr 12, 2009 9:33 pm

Didn't read your code but this is how to convert an int to a string.

Java:

int number = 9000;
String value = String.valueOf(number);

In case you are wondering on how to convert a char value into a String,

Java:

char c = 'k';
String value = Character.toString(c);

ahmhum · **Posted:** Sun Apr 12, 2009 10:10 pm

it doesn't work even when i did that

ahmhum · **Posted:** Sun Apr 12, 2009 10:20 pm

ok nvm it did work

ahmhum · **Posted:** Sun Apr 12, 2009 10:37 pm

ok now i want to convert char value to String but what you told me to do Dark, it doesn't work

Dusk Eagle · **Posted:** Sun Apr 12, 2009 10:38 pm

Just out of curiosity, are you making a Death Note game?

Tony · **Posted:** Sun Apr 12, 2009 10:51 pm

You'd think that he'd actually use "Shinigami" then. The reference to "Hollow" makes me think Bleach, although I haven't seen nearly enough of that series to be sure.

@ahmhum -- in what way does it not work?

ahmhum · **Posted:** Sun Apr 12, 2009 10:57 pm

it says tht the char is not defined
char c = 'k';
String value = Character.toString(c);

so (c) is not defined is what i get
nd yea its a bleach game

ahmhum · **Posted:** Sun Apr 12, 2009 11:00 pm

oo and i want it to read two character so like 1A and not just 1 or A or w/e

ahmhum · **Posted:** Mon Apr 13, 2009 12:11 am

ok this is what I want to convert from char to String

Java:

//Allow user to input number to see an object.
public static void player1Choose(String namePlayer1,String namePlayer2)
{

e.clear();
d.clear();

//Set integers for choose selection.
int number;
int input=0;

//Prompt user to input data and read the character.
player1ChooseText(namePlayer1);

backgroundForEConsole();
itsYourTurnText(e);
makeAMoveText(e);
e.setTextColor(Color.white);
e.setTextBackgroundColor(Color.blue);
e.println(namePlayer1+" Your score is: "+scorePlayer1+"");

char play = d.getChar();;

if (play == '1')
{
input = 1;
}
if (play == '2')
{
input = 2;
}

if (play == '3')
{
input = 3;
}
if (play == '4')
{
input = 4;
}
if (play == '5')
{
input = 5;
}
if (play == '6')
{
input = 6;
}
if (play == '7')
{
input = 7;
}
if (play == '8')
{
input = 8;
}
if (play == '9')
{
input = 9;
}

e.clear();
d.clear();
//Set number selection.
number=input;

//Try/catch construct for invalid entry.
try
{
numberForPlayer1(number,namePlayer1,namePlayer2);

}

catch (NumberFormatException e)
{
invalidEntry();
gameGrid();
player1Choose(namePlayer1,namePlayer2);
}

}//choose method

thnx in advance

Tony · **Posted:** Mon Apr 13, 2009 12:29 am

code:

if (play == '1')
{
input = 1;
}
if (play == '2')
...

No.

ahmhum · **Posted:** Mon Apr 13, 2009 1:20 am

what do u mean no

wtd · **Posted:** Mon Apr 13, 2009 2:17 am

He means that's the wrong way to write that bit of code.

Notice the pattern. Make your code simpler.

wtd · **Posted:** Mon Apr 13, 2009 2:19 am

Also horribly wrong:

code:

if (face==1)
{
//Calling upon the hair method.
hairQuestion(sword, face);
}

if (face==2)
{
//Calling upon the hair method.
hairQuestion(sword, face);
}

Dark · **Posted:** Mon Apr 13, 2009 10:05 am

those should be else ifs, after the first if.

Also, use a switch statement for those ifs.

Or, better yet, let play = input.

parse the char into an int.

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