randomizing

[rto]

in turing all i would have to do is enter randint(variable, range) but instead java has to be difficult. anybody able to give me the method i would use? i want to be able to have 4 possible choices and java will randomly pick one. (ie. choice a will be referred to '1', choice b will be referred to '2' etc.)

any ideas?

[Insectoid]

use Math.random (). This returns a random decimal between 0 and 1. So (int) (Math.random ()*4) will give a random number between 1 and 4 (I think...Haven't used it in a while). (int) will convert the random number to an integer. I don't think it rounds, I think it just cuts off the decimal..Though I may be wrong...

[OneOffDriveByPoster]

insectoid @ Tue Nov 25, 2008 4:09 pm wrote:

use Math.random (). This returns a random decimal between 0 and 1. So (int) (Math.random ()*4) will give a random number between 1 and 4 (I think...Haven't used it in a while). (int) will convert the random number to an integer. I don't think it rounds, I think it just cuts off the decimal..Though I may be wrong...

The range is [0, 1). So if you have choices in range [1, 4], you need to multiply by 4 to get range [0, 4). Cast to int to get [0, 3] and add one to get [1, 4].

[Horus]

there's so many random function is java.

this is what I use:

import java.util.Random;


rdmNum=Random.nextInt(x);

the range is 0 to x-1

[Sur_real]

There are so many you mean
(sorry, just can't help myself)

[Tony]

What, that's it?

Horus @ Tue Nov 25, 2008 10:47 pm wrote:

there's so many random function is java.

There are so many random functions in Java.

[Sur_real]

lol didn't notice that...

[[Gandalf]]

Question's already been answered thoroughly, locked.