Trying to parse a string....

[blissfullydysphoric]

Hi, I'm trying to take a 10 digit number and take its individual parts... So I take the number as a string and I am trying to get each character in the string to go into an integer array using the atoi() command but it gives me an error on the line that i use the atoi....

code:

#include <stdio.h> #include <math.h> #include <stdlib.h> int main(void) {     int isbn[10];     char array1[10];     int i;     int temp;     printf( "Please enter the ISBN number:\n" );     scanf("%s",array1);     puts(array1);     isbn=atoi(array1);     printf("%d",isbn[0]);     printf("\n");     return 0; }

[md]

Look up the documentation on atoi, but basically you are trying to use it to do something it doesn't do.

atoi returns an integer, not an array of integers.

[blissfullydysphoric]

ok thanks.... I can get it to put all of the string into one integer but not an array..... do you have any other suggestions on how to do this?

[OneOffDriveByPoster]

blissfullydysphoric @ Wed Nov 05, 2008 8:55 pm wrote:

ok thanks.... I can get it to put all of the string into one integer but not an array..... do you have any other suggestions on how to do this?

You did say a 10 digit number. Did you try 2147483648? Why are you using atoi()? Do you have to? Standard C says that the characters '0' to '9' are consecutive values. That can help.

[md]

If your goal is to copy each digit of the number into a different position in an integer array then teh simple way is to set integer_array[i] to character_array[i] - '0'

Why that is and how to use it to your advantage I leave to you.

[blissfullydysphoric]

@md
Thanks that helped alot... I tried the subtract zero thing before but i guess I needed the ' ' around it.