Converting Int to Char

[Prince Pwn]

I need to convert an Integer into a Character so I could use a for loop to assign a number to a variable when I press a 1 2 3 or 4. For some reason it isn't reading the for loop input.

I'm basically needing a way to automate:

Java:

if (key == '1')                 amount = 1;             else if (key == '2')                 amount = 2;             else if (key == '3')                 amount = 3;             else if (key == '4')                 amount = 4;

Here is my code:

Java:

public boolean keyDown (Event moving, int key)     {         if (introScreen)         {             if (key == Event.ESCAPE)                 System.exit (0);             if (key == Event.RIGHT)                 amount++; // WORKS!             else if (key == Event.LEFT)                 amount--; // WORKS!             for (int i = 1 ; i <= maxBall ; i++) // counts to 4             {                 if (key == char (i))  // if i press any number, 1 - 4 // DOESNT WORK!                     amount = i;    // amount becomes equal to the number I press             }             if (key == Event.ENTER)                 introScreen = false;         }

[HeavenAgain]

hello, the problem should be

if (key == char (i))

what do you mean by char (i) ? trying to cast an int to a char ? then it should be

code:

(char)(12)

since i is in the for loop, i dont get the part where you enter a number? but anyways
converting a String using java the code is

code:

Integer.parseInt();

example

code:

Integer.parseInt("100");

that would give you 100 as integer

by the way,i suggest you use another variable for this
i hope this helps?

[OneOffDriveByPoster]

Prince Pwn @ Mon May 28, 2007 10:33 am wrote:

Java:

for (int i = 1 ; i <= maxBall ; i++) // counts to 4             {                 if (key == char (i))  // if i press any number, 1 - 4 // DOESNT WORK!                     amount = i;    // amount becomes equal to the number I press             }

Consider this: (char)0x30 is '0'.

So your conversion should be (char)(i | 0x30)--this is okay because you control the value of "i"; this will not work with # > 9.
You can also check out Java characters and their relation to Unicode.

[Prince Pwn]

Thankyou.