Difference between break; and continue;

[ownageprince]

Sorry if its a dumb question...i tried them out and i think that they do same thing...i tried them in if structures and switch...so can anyone please explain the difference because why make two separate commands that do the same thing right?

[wtd]

In a loop, continue will advance immediately to the next step through the loop.

[r.3volved]

....break will break you out of the loop and run the code that follows it

try this and see the difference:

code:

int x = 0; for( x; x != 10; ++x ) {    if( x == 5 ) break; } cout << x;

code:

int x = 0; for( x; x != 10; ++x ) {    if( x == 5 ) continue; } cout << x;

[ericfourfour]

I think he asked for the purpose in an if and case statement. I'm not really knowledgeable on this front so I'll leave it up to someone else to assist you.

[Monstrosity_]

ownageprince wrote:

Sorry if its a dumb question...i tried them out and i think that they do same thing...i tried them in if structures and switch...so can anyone please explain the difference because why make two separate commands that do the same thing right?

I suggest you turn up the warning level on your compiler because this is a constraint violation. In any case, I'll give you the definition in C, since you failed to specify which language you are using.

ISO C9899:1990 wrote:

Constraints
A continue statement shall appear only in or as a loop body.

Semantics
A continue statement causes a jump to the loop-continuation portion of the smallest enclosing iteration statement; that is, to the end of the loop body.

<examples snipped>

Constraints
A break statement shall appear only in or as a switch body or loop body.

Semantics
A break statement terminates execution of the smallest enclosing switch or iteration statement.

[ownageprince]

r.3volved wrote:

try this and see the difference:

code:

int x = 0; for( x; x != 10; ++x ) {    if( x == 5 ) break; } cout << x;

code:

int x = 0; for( x; x != 10; ++x ) {    if( x == 5 ) continue; } cout << x;

so in the continue one it will continue the for loop when x hits 5 and will display 10 after the loop is done but in the break one it will stop right away and then go to the cout<<x; right?

if so then why put continue or is there another purpose to it?

also am using microsoft visual C++ 6.0
ty for replys all!

[ownageprince]

hang on a sec:

for(int x=0;x<10;x++)
{
if(x==5)
continue;
cout<<x<<endl;
}
this will cout x everytime until it hits that if statement right? because continue will tell it to go to the starting the for loop and skip the following in the loop?

[wtd]

What does the following output?

code:

for (int i = 0; i < 10; i++) {     if (i % 2 == 0)     {         continue;     }     std::cout << i << std::endl; }

[ownageprince]

does it output:
1
3
5
7
9

[wtd]

If you understand break and continue, you'll be able to give a confident answer.

[md]

Not to belittle anyone here.. but has anyone tried oh say running the code? Instead of guessing at the output of something so trivial try running it and see what happens!

[ownageprince]

lolz ty md buh understand first then type code or what the heck...anyways i took your advice and ran it and i was right
ty all who replied. appreciate that!

[TheFerret]

ownageprince wrote:

lolz ty md buh understand first then type code or what the heck...anyways i took your advice and ran it and i was right
ty all who replied. appreciate that!

Posting like this makes you seem like an idiot and make less people want to help you since what you are saying is unclear, it has a rude quality about it and is spoken in "l33t speak" which makes your point even more unclear... It would be wise to use proper grammar and typing skills here in the future so people will help you more willingly...

[Andy]

err how is that l33t speak?

[md]

That's not 1337; that's just horrible writing.