Help with algorithm in C

[Dreadnought]

Panphobia wrote:

I figured it out, the C compiler I am using is weird, when building a propositional statement like a&&b == b && c you need brackets, (a && b) == (b && c)

That's not your compiler, that's the C standard, (look up operator precedence).

Did that come up in the snippet you posted?

[Insectoid]

That's not an issue with the compiler, that's part of the C spec. == takes precedence over &&. In your situation, it evaluates b == b first, which of course is true, so your equation simplifies to a&&c.

But yeah, the brackets would have fixed it.

EDIT: Damnit, Dreadnaught.

[Panphobia]

No it was the other way around, a == b && b == c, sorry, as you can see the xEnd = uX && yEnd == uY, so I needed to change it to (xEnd == uX) && (yEnd == uY)