Computer Science Canada [source] Bezier Curve 
Author:  Catalyst [ Tue Mar 02, 2004 9:17 pm ]  
Post subject:  [source] Bezier Curve  
Implementation of a 4point Bezier Curve Translated (and simplified) from my c++ implementation

Author:  zylum [ Tue Mar 02, 2004 9:23 pm ] 
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wow that is really nice... im going to try and recreate that without looking at the code +20 bits zylum 
Author:  Tony [ Tue Mar 02, 2004 10:38 pm ] 
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sweet anyone wants to write up a vector design app (adobe illustrator) in turing? 
Author:  AsianSensation [ Tue Mar 02, 2004 11:12 pm ] 
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that is really really nice 
Author:  jonos [ Wed Mar 03, 2004 8:15 am ] 
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yeah, awesome. 
Author:  recneps [ Wed Mar 03, 2004 3:53 pm ] 
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Nice indeed. That has many many possibilities. 
Author:  shorthair [ Wed Mar 03, 2004 5:09 pm ] 
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Once again , 2 thumbs up , just a quality app catalyst , i really like it , your code is just crazy you have areally really unique style 
Author:  the_short1 [ Fri Mar 12, 2004 2:16 pm ] 
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crzy,,,, taht lookz realy nice... and black backround.. YAY someone makes it look good... does anyone know the proper slope to get a circle... like for drawing a line at a central point and rotating it do a nice circle.. whenever i try i only get it to / and \ not round x += ? y +=? y := ?x + ? blah blah blah... i should know this cuz we did sometihgn similiar to it in math.. but i forget the slope now but i dont got my bookz with me... thx.. 
Author:  jonos [ Fri Mar 12, 2004 3:22 pm ] 
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you have to square the y or x coordinates to get a parabola (i think, we haven't done that in math yet). 
Author:  the_short1 [ Fri Mar 12, 2004 3:31 pm ] 
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i have the exact formula but its at school . . im on march break as as yesterday... 
Author:  Tony [ Fri Mar 12, 2004 4:03 pm ] 
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isn't it something like x*x + y*y = r*r ? 
Author:  Delos [ Fri Mar 12, 2004 6:21 pm ] 
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That only applies to a circle from the origin. I believe the general eqn for a cirle on a Cartesian place is: (yp)^2 + (xq)^2 = r^2 Or something to that effect...urgh..Gr11 maths haunting again. 
Author:  the_short1 [ Fri Mar 12, 2004 10:36 pm ] 
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thanxTony... thats it ..or at least thats was the formula i remember.... 
Author:  SuperGenius [ Fri Mar 19, 2004 2:38 pm ] 
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the formula for the radius of a circle that my tracher told us is: r=sqrt ((x2x1)** + (y2y1)**) 
Author:  jonos [ Fri Mar 19, 2004 3:07 pm ] 
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i think they are the same, because one of your x,y is the center of the circle and the other is a point on the circle, so the radius is the the length of that (i think) 
Author:  the_short1 [ Fri Mar 19, 2004 5:21 pm ] 
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homer made me the program i wanted ... it uses cos and sin.... i dont fully understand how to integrate math into compsci... thats was gr.11 for... either way... its all good 
Author:  SuperGenius [ Fri Mar 19, 2004 8:15 pm ] 
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jonos wrote: i think they are the same, because one of your x,y is the center of the circle and the other is a point on the circle, so the radius is the the length of that (i think)
You are correct. 
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