Computer Science Canada cout with pointers |
| Author: | hamid1455 [ Sun Mar 31, 2013 1:04 pm ] |
| Post subject: | cout with pointers |
Say I have a pointer like this: double meow = 0; double * pDouble = &meow; Then cout << &pDouble; will print the memory address that pDouble is pointing to, right? So then what is the memory address that I get when I output just plain old pDouble? Also, outputting *pDouble gives me the value of the pointer or the value of what the pointer is pointing to? Thanks in advance guys. |
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| Author: | linuxp [ Sun Mar 31, 2013 1:13 pm ] |
| Post subject: | RE:cout with pointers |
pDouble = &meow = address of meow *pDouble = meow = value of meow &pDouble = address of pDouble itself |
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| Author: | hamid1455 [ Sun Mar 31, 2013 1:42 pm ] |
| Post subject: | Re: cout with pointers |
so I could make a pointer that points to another pointer? |
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| Author: | nullptr [ Sun Mar 31, 2013 3:34 pm ] |
| Post subject: | Re: cout with pointers |
Yes. And you could make a pointer that points to a pointer that points to a pointer if you wanted to. int************ p; is valid C++ code, though I can't think why you would need that many levels of pointers. |
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