Computer Science Canada Boolean Algebra |
| Author: | omni [ Sat Feb 05, 2005 12:37 pm ] |
| Post subject: | Boolean Algebra |
I'm having some troubles understanding boolean algebra. Simplify: y = ((A*B)*C) + (A*C) y = ((A*B) + A) * C is this fully simplified, or is it even right? |
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| Author: | Andy [ Sat Feb 05, 2005 3:56 pm ] |
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errr no... y = ((A*B)*C) + (A*C) well you know * is communitive so you can rewrite it as y = ((A*C)*B) + (A*C) then you can factor out an (A*C) leavin u with y = (A*C)*(B+1) and since B+1 is always 1, you have y = (A*C)*1 leaving you with simply y = A*C |
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| Author: | wtd [ Wed Feb 09, 2005 3:40 am ] |
| Post subject: | |
I must be fuzzy on math after years away from the classroom. Where do you get that B + 1 is always 1? |
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| Author: | Martin [ Wed Feb 09, 2005 7:54 am ] |
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Boolean Algebra. + is essentially OR. Anything or TRUE is always TRUE. |
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| Author: | wtd [ Wed Feb 09, 2005 3:43 pm ] |
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Ah yes. |
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