pokerface wrote:
You get what i mean?
The algorithm I provided does exactly what you want.
Computer Science Canada patterns |
| Author: | pokerface [ Fri Oct 15, 2004 5:12 pm ] |
| Post subject: | patterns |
im trying to make a program that out puts a pattern depending of what number u input. ****************************************** var num : int put "Enter a negative number to stop." loop put "How many patterns do you want? " .. get num exit when num <= 0 for count : 1 .. num put "!" .. end for put "" end loop ******************************************* example of what im looking for (if you type a 8 then u get "!@#!@#!@" as the answer but if u type 1 then u get "!" or a 9 then u get "!@#!@#$!@#") need me 2 further explain then please ask me for me to answer what i mean! |
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| Author: | AsianSensation [ Fri Oct 15, 2004 9:08 pm ] | ||
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well, I suggest a bit of a string manipulation. declare a string variable, something like this:
and instead of outputting the "!".. in your code, output a random letter of the string above. |
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| Author: | wtd [ Fri Oct 15, 2004 9:14 pm ] |
| Post subject: | |
Get a number of characters. Create a counter variable, set it to 1. Create an empty string variable to hold the output pattern. Start a loop. If the counter is greater than the number of characters, exit the loop. Add "!" to the string. Increase the counter by one. If the counter is greater than the number of characters, exit the loop. Add "@" to the string. Increase the counter by one. If the counter is greater than the number of characters, exit the loop. Add "#" to the string. Increase the counter by one. End the loop. |
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| Author: | AsianSensation [ Fri Oct 15, 2004 9:19 pm ] |
| Post subject: | |
wait, what was the pattern? like if I input 1, it out puts "!" 2 and "!@" 3 and "!@#" 4 and "!@#$" or something? but 8 was "!@#!@#!@", so it was taken in groups of 3s and 9 was "!@#!@#$!@" which was weird because it had 10 chars and weird repeating patterns. I suggest a further explaination. |
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| Author: | pokerface [ Fri Oct 15, 2004 9:52 pm ] |
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i want it to put ! if the user asked to put 1 symbol but !@ if the user asked for 2 symbols. its werid but i want it to add # if they ask for 3 symbols!!! ***************************************** How many patterns do you want? 1 ! How many patterns do you want? 2 !@ How many patterns do you want? 3 !@# How many patterns do you want? 4 !@#! How many patterns do you want? 5 !@#!@ How many patterns do you want? 6 !@#!@# How many patterns do you want? 7 !@#!@#! ******************************************** You get what i mean? |
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| Author: | wtd [ Fri Oct 15, 2004 10:15 pm ] |
| Post subject: | |
pokerface wrote: You get what i mean?
The algorithm I provided does exactly what you want. |
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| Author: | pokerface [ Fri Oct 15, 2004 10:26 pm ] |
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sorry that was directed to AsianSensation |
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| Author: | wtd [ Fri Oct 15, 2004 10:34 pm ] |
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I know. Just seemed kind of odd that you were still fishing when I'd thrown out a way of getting it done. |
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| Author: | AsianSensation [ Fri Oct 15, 2004 11:58 pm ] |
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yah, I was confused about the Quote: a 9 then u get "!@#!@#$!@#" I didn't see where the "$" came from. |
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| Author: | pokerface [ Sat Oct 16, 2004 9:03 am ] |
| Post subject: | |
wtd i dont understand! could u show me an example? dont worry this is not for school! i just wanted to make a pattern cause a question for school is very simular! |
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| Author: | AsianSensation [ Sat Oct 16, 2004 11:26 am ] | ||
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I guess something like this:
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| Author: | pokerface [ Sat Oct 16, 2004 12:15 pm ] |
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ty for ur time! |
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| Author: | wtd [ Sat Oct 16, 2004 2:17 pm ] |
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pokerface wrote: wtd i dont understand! could u show me an example? dont worry this is not for school! i just wanted to make a pattern cause a question for school is very simular!
I won't show you in Turing, because then you could just copy and paste. 
[code]# get an integer representing the number of characters num_chars = gets.to_i counter = 1 output = "" loop do break if counter > num_chars output += "!" counter += 1 break if counter > num_chars output += "@" counter += 1 break if counter > num_chars output += "#" counter += 1 end loop puts output |
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| Author: | Andy [ Sat Oct 16, 2004 2:20 pm ] |
| Post subject: | |
wtd wrote: I won't show you in Turing, because then you could just copy and paste.
i thought it was cuz u dont have turing on ur comp lol |
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| Author: | wtd [ Sat Oct 16, 2004 2:22 pm ] |
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dodge_tomahawk wrote: wtd wrote: I won't show you in Turing, because then you could just copy and paste.
i thought it was cuz u dont have turing on ur comp lol For something this simple, I can manage to write code that would work. |
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| Author: | pokerface [ Sun Oct 17, 2004 7:27 pm ] |
| Post subject: | |
thanks ppl! but do u know how i could seperate even numbers with odd numbers? ps without mods please |
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| Author: | AsianSensation [ Sun Oct 17, 2004 7:58 pm ] |
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you can use div if some number div 2 = some number / 2 then it's even. |
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| Author: | pokerface [ Sun Oct 17, 2004 8:14 pm ] |
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is there an other way? i just want to know as many ways as possible? |
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| Author: | AsianSensation [ Sun Oct 17, 2004 10:19 pm ] |
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you can always convert it to a string, and check the last digit, if it's 0, 2, 4, 6, 8 then it's even, or else it's odd. |
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| Author: | wtd [ Sun Oct 17, 2004 11:01 pm ] | ||||
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pokerface wrote: thanks ppl! but do u know how i could seperate even numbers with odd numbers? ps without mods please
In integer arithmetic, dividing one integer by another always gives us another integer. This is why
gives us 1. So we need a way of finding the remainder. "mod" allows for that. Obviously, if we divide an even number by 2, there should be no remainder. So if the result of someNumber mod 2 is 0, then someNumber is even.
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| Author: | beard0 [ Thu Oct 21, 2004 8:08 pm ] | ||
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true=even false=odd |
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