Computer Science Canada Is there an easy way to make these if statements be one? |
| Author: | joe333 [ Tue Apr 13, 2004 7:16 pm ] |
| Post subject: | Is there an easy way to make these if statements be one? |
Is there an easy way to make these smaller? Like in a loop or something? i'm making a hex to dec convertor. if input1 = "A" then input2 := intstr (A) end if if input1 = "B" then input2 := intstr (B) end if if input1 = "C" then input2 := intstr (C) end if if input1 = "D" then input2 := intstr (D) end if if input1 = "E" then input2 := intstr (E) end if if input1 = "F" then input2 := intstr (F) end if |
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| Author: | omni [ Tue Apr 13, 2004 7:42 pm ] |
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Right off the top of my head, you can make it like if input1="A" then 'command' elsif input1="B" then ... ... so on end if That means ONLY ONE of those conditions can be true. Not sure if intstr(A) will work, that converts an integer to a string. Unless if 'A' is a variable of integer type, don't think that will work |
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| Author: | EDEN-E [ Tue Apr 13, 2004 7:57 pm ] |
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If you dont want to use 'IF' statement, you can use "CASE" case input1 of label "A" : input2 := intstr(A) label "B" : input2 := intstr(B) label "C" : input2 := intstr(C) label "D" : input2 := intstr(D) label "E" : input2 := intstr(E) label "F" : input2 := intstr(F) end case |
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| Author: | Raugrist [ Tue Apr 13, 2004 8:07 pm ] | ||
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I don't know why you're doing intstr, but whatever...
From the looks of your post, that should do it quite nicely. Basically, it checks if input1 is a letter between A and F, and if it is, it gets the number value for that letter (you are converting from Hex, so A = 11, B = 12, ..., F = 15), converting the value to a string and putting it in input2. |
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