I believe that the answer is 1.9 m/s [down].
Here's how I did it:
Computer Science Canada Final Velocity Question |
| Author: | hamid14 [ Wed Oct 13, 2010 3:40 pm ] |
| Post subject: | Final Velocity Question |
I think I've solved this question correctly, but I am not really sure. My answer was that the final velocity is 5.2 m/s [down] Also, I used this formula. delta D = V1 * delta T - 1/2 * a * delta T squared here's the question: The acceleration due to gravity on the moon is 1.6 m/s squared [down]. If a baseball was thrown with an initial velocity of 4.5 m/s [up], what would its velocity be after 4.0s? |
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| Author: | andrew. [ Wed Oct 13, 2010 4:29 pm ] |
| Post subject: | RE:Final Velocity Question |
I believe that the answer is 1.9 m/s [down]. Here's how I did it: |
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| Author: | TerranceN [ Wed Oct 13, 2010 4:30 pm ] |
| Post subject: | RE:Final Velocity Question |
Because there is constant acceleration, Vf = Vi + at Next you need to set a direction as positive, I chose up Then you can just calculate your answer (remember that acceleration is down so it will be negative) Vf = 4.5 - 1.6 * 4 Vf = -1.9 Since negative represents down the final answer is 1.9 m/s [down]. Also, what other formula did you use (probably the Vf version of that one?), what you posted would only give you the displacement. @andrew:  beat me by less than a minute, and you even had a fancy picture... |
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| Author: | hamid14 [ Wed Oct 13, 2010 4:35 pm ] |
| Post subject: | Re: Final Velocity Question |
he didnt give us that formula. thanks |
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| Author: | andrew. [ Wed Oct 13, 2010 4:51 pm ] |
| Post subject: | RE:Final Velocity Question |
You can create that formula by using the definition of acceleration: a = ∆v/∆t (the change in velocity divided by the change in time) So, a = (v2 - v1)/∆t Now rearrange: a∆t = v2 - v1 a∆t + v1 = v2 v2 = v1 + a∆t |
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